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Diano4ka-milaya [45]
3 years ago
6

Which of the ratio pairs are equivalent? A.4:10 , 2:5 B. 5:4 , 10:6 C. 1:3 , 1:4

Mathematics
2 answers:
katrin [286]3 years ago
8 0

Answer:

a

Step-by-step explanation:

eduard3 years ago
4 0

Answer:

A

Step-by-step explanation:

4:10 can be reduced to 2:5 without changing the ratio.

With B, 10 can be reduced to 5 by dividing by 2 but 6 divided by 2 is not 4.

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Answer:

50, 52, 54, 55, 56, 56, 64, 65, 68, 74, 74, 76, 77, 77, 80, 81,  90, 91, 95, 99,

Step-by-step explanation:

6 0
3 years ago
L(-5,-6) and M (3,8)<br>​
leonid [27]

Answer:

y = 7 /4 x + 11 /4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Whats greater -4 or -10
anygoal [31]
-4 because it is closer to the 0
5 0
3 years ago
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Please can someone help me with this question
sasho [114]

<em>Answer:</em>

<em>r = -</em>\frac{6a}{1-5m^2}<em />

<em>Step-by-step explanation:</em>

<em>Rewrite the equation as </em>\sqrt{x} 6a+r/5r<em>  = m</em>

<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>

<em>(</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> = m^2</em>

<em>Then, you simplify each of the equation. </em>

<em>Rewrite: (</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> as </em>\frac{6a+r}{5r} = m^{2}<em />

<em>Remove any parentheses if needed.</em>

<em>Solve for r. </em>

<em>Multiply each term by r and simplify."</em>

<em>Multiply both sides of the equation by  5.</em>

<em>6a+r= m^2r⋅(5)</em>

<em>Remove parentheses.</em>

<em>Move 5   to the left of (m ^2)  r </em>

<em>6a+r=5m^2)r</em>

<em>Subtract  5m^2)r  from both sides of the equation.</em>

<em>6a+r-5m^2)r=0</em>

<em>Subtract  6a  from both sides of the equation.</em>

<em>r-5m^2)r=-6a</em>

<em>Factor  r out of  r-5m^2)r  </em>

<em>r(1-5m^2)=-6a</em>

Divide each term by 1-5m^2 and simplify.

r = - \frac{6a}{1-5m^2}

There you go, hope this helps!

4 0
4 years ago
The sides of a right triangle are x, x+21, and x+27. what is the length of the hypotenuse
mina [271]
Answer: 51 uinits

The three numbers are x , x + 21 and x + 27. 
The greatest of the 3 numbers is x + 27, so x + 27 has to be the hypotenuse.

----------------------------------------------
Pythagoras Theorem
----------------------------------------------

a² + b²  = c²

x² + (x+21)² = (x+27)²

x² + x² + 42x + 441 = x² + 54x + 729

x² - 12x -288 = 0

(x - 24)(x + 12) = 0

x = 24 or x = -12 (rejected, length cannot be negative)

----------------------------------------------
Find hypotenuse
----------------------------------------------
 Hypotenuse = x + 27 = 24 + 27 = 51 units

-----------------------------------------------
Answer: 51 units
----------------------------------------------

3 0
4 years ago
Read 2 more answers
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