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3 years ago

The sum of four consecutive odd integers is 328. What are the integers? (show your work)

Mathematics

1 answer:

Minchanka [31]3 years ago

8 0

Answer:

79, 81, 83, and 85

Step-by-step explanation:

x = 1st integer

x+2 = 2nd

x+4 = 3rd

x+6 = 4th

328 = sum

x+x+2+x+4+x+6 = 328

328/4 = 82

The 4 integers are the 2 odd integers on either side of 82 and closest to 82

That would be 79, 81, 83, and 85.

79 + 81 + 83 + 85 = 328

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What is the distance between the building B (4, 6) and the station K (–6, –2)? Use a calculator to round to the nearest tenth.

Svetllana [295]

Answer:

The answer is

<h2>12.8 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

B (4, 6) and K (–6, –2)

The distance is

$|BK| = \sqrt{ ({4 + 6})^{2} + ({6 + 2})^{2} } \\ = \sqrt{ {10}^{2} + {8}^{2} } \: \: \: \: \: \: \: \: \: \\ = \sqrt{100 + 64} \: \: \: \: \: \: \: \: \: \\ = \sqrt{164} \\ = 2 \sqrt{41} \\ = 12.80$

We have the final answer as

<h3>12.8 to the nearest tenth</h3>

Hope this helps you

5 0

3 years ago

If x²-5x +1 =0, what is the value of -<br><img src="https://tex.z-dn.net/?f=%28x%20%2B%20%20%5Cfrac%7B1%7D%7Bx%7D%20%29%20%20" i

ra1l [238]

<h3>Answer: 5</h3>

=================================================

Work Shown:

x^2 - 5x + 1 = 0

x^2 + 1 - 5x = 0

x^2 + 1 = 5x

(x^2 + 1)/x = 5 .... where x is nonzero

(x^2)/x + (1/x) = 5

x + (1/x) = 5

---------------

An alternative method involves solving the original equation using the quadratic formula. After you get the two roots x = p and x = q, you should be able to find that p + 1/p = 5 and also q + 1/q = 5 as well.

In this case,

p = (5 + sqrt(21))/2

q = (5 - sqrt(21))/2

8 0

3 years ago

Read 2 more answers

You are choosing between two health clubs. Club A offers membership for a fee of $12 plus a monthly fee of $28. Club B offers me

EleoNora [17]

A has fixed one time fee of $12 and if you go to it say "m" months you pay $28 for each month, so your total cost at A is really 12 + 28m.

B has a fixed one time fee of $20 and if you go to it "m" months you pay $26 for each month, so you total cost at B is 20 + 26m.

how many months for the cost to be the same?

$\stackrel{A}{12+28m}=\stackrel{B}{20+26m}\implies 12+2m=20\implies 2m=8\implies m=\cfrac{8}{2}\implies m=4$