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Pavel [41]
3 years ago
7

F(x)=2x-1 and g(x)=6x-2. Write a formula for (fg)(x)

Mathematics
1 answer:
Alina [70]3 years ago
4 0
Answer:
2(6x-2)-1

Explanation:
Plug in g(x) for x
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The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
A 26-foot long ladder is leaning against a building at a 60 degree angle with the ground. Which of the following equations can y
Sati [7]

Answer:

22.5 feet (to the nearest tenth).

Step-by-step explanation:

The equations have not been given but still the question can be solved. The ladder lying with a building makes a right angled triangle, in which the ladder is the hypotenuse, the building is the perpendicular, and the ground is the base. The length of the ladder (hypotenuse) is 26 feet and the angle with the ground is 60 degrees. The required length to be found is the length of the building (perpendicular). So the following formula will be used:

sin θ = Perpendicular/Hypotenuse.

Substituting in the equation gives:

sin60 = p/26.

p = 26*sin60.

p = 22.5 (to the nearest tenth).

The approximate height of the building is 22.5 feet!!!

4 0
4 years ago
Read 2 more answers
What is not a problem modular division is used for?
Oksana_A [137]

Answer:

First let's define what modular arithmetic is, what would come is an arithmetic system for equivalence classes of whole numbers called congruence classes.

Now, the modular division is the division in modular arithmetic.

Answering the question, a modular division problem like ordinary arithmetic is not used, division by 0 is undefined. For example, 6/0 is not allowed. In modular arithmetic, not only 6/0 is not allowed, but 6/12 under module 6 is also not allowed. The reason is that 12 is congruent with 0 when the module is 6.

4 0
3 years ago
I dont understand this I need to show work to. Please help me. ​
ra1l [238]

Answer:

a. m = Vd

b. 6.012g

Step-by-step explanation:

a.  you need to rearrange the equation so that you're solving for m. you can do so by multiplying both sides by V so you end up with

Vd = m or m = Vd (i prefer writing it this was purely cause it looks better)

b. now, you can plug in each value into the new equation so you get

5.01g/cm3 x 1.2 cm3 = m

from here you just multiply as normal

6 0
3 years ago
a group friends ordered 3 burgers and 3 medium fries for a total of 20.25 .Another group of friends ordered 5 burgers and 8 medi
matrenka [14]
Answer: a burger is $5.25, fries are $1.50

b = burger, f = fries
3b + 3f = 20.25
5b + 8f = 38.25

First, solve for b in terms of f
3b = 20.25 - 3f
b = 6.75 -f

Then substitute that for b in the other equation to solve and get a numerical value for f.

5(6.75 -f) + 8f = 38.25
33.75 -5f +8f = 38.25
33.75 + 3f = 38.25
3f = 4.5
f = 1.5

Now substitute that in to get a numerical value for b
b = 6.75 - 1.5
b = 5.25

Checking the math:
3b + 3f = 20.25
3(5.25) + 3(1.5) = 15.75 + 4.5 = 20.25
5 0
3 years ago
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