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3 years ago

What is (x+2)(x-2) equal ?

Mathematics

2 answers:

belka [17]3 years ago

8 0

Answer:

x^2 - 4

Step-by-step explanation:

since it is in the form of

a^2 - b^2 = (a + b)(a - b)

u can directly write x^2 - 2^2

=x^2 - 4

process :

(x + 2)(x - 2)

=x(x - 2) + 2(x - 2)

=x^2 - 2x + 2x - 4

=-2x and plus 2x gets cancel

=x^2 - 4

gizmo_the_mogwai [7]3 years ago

7 0

(x - 4)^2 , i hope this helps

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How is the sum expressed in sigma notation? 11 + 17 + 23 + 29 + 35 + 41

Ann [662]

<h3>The sum expressed in sigma notation is:</h3>

$11+17+23+29+35+41=\sum\limits_{i=1}^{6}5+6i$

Solution:

Given that,

11 + 17 + 23 + 29 + 35 + 41

We have to express the sum in sigma notation

Analyse the series

5 + 6(1) = 11

5 + 6(2) = 17

5 + 6(3) = 5 + 18 = 23

5 + 6(4) = 5 + 24 = 29

5 + 6(5) = 5 + 30 = 35

5 + 6(6) = 5 + 36 = 41

Thus the series goes on like this:

5 + 6(n) , where n = 1 to 6

This can be expressed in sigma notation as:

$11+17+23+29+35+41=\sum\limits_{n=1}^{6}5+6n$

We can expand the sigma notation and verify the results

$\sum\limits_{i=1}^{6}5+6i=(5+6(1))+(5+6(2))+(5+6(3))+(5+6(4))+(5+6(5))+(5+6(6))\\\\\\\sum\limits_{i=1}^{6}5+6i=(5+6)+(5+12)+(5+18)+(5+24)+(5+30)+(5+36)\\\\\\\sum\limits_{i=1}^{6}5+6i=11+17+23+29+35+41$

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miskamm [114]

Answer:

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Step-by-step explanation:

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-5y-50

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Step-by-step explanation:

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