Vertex form is
y = a(x - b)^2 + c
here a = -3 and b = -18 so we have
y = a(x + 3)^2 - 18
when x = 0 , y= 0 ( the y-intercept) so:-
0 = a(3^)2 - 18
9a = 18
a = 2
so the parabola is y = 2(x + 3)^2 - 18
x intercepts found as follows:-
2(x + 3)^2 - 18 = 0
(x + 3)^2 = 9
x + 3 = +/- sqrt9 = +/- 3
so x intercepts are 0 and -6 Answer
First distribute and then combine like terms, answer: -1.42x+2.8
Answer: 22
explanation: the easiest way is to separate one of the diagonals into a triangle and use the pythagorean theorem.
a^2 + b^2 = c^2
4^2 + 3^3 = c^2
16 + 9 = c^2
25 = c^2
5 = c
you now know that both of the diagonals have a length of 5.
by counting the units on the two straight, you know that their length is 6.
6 + 6 + 5 + 5 = 22
Answer:
the answer is 45
Step-by-step explanation:
Step 3, since it is Graphed.
18*1=18, 18*2=36, 18*3=54, and it said 2/3, right? 36 is 2/3 of 54.
