Find the x-intercepts if the parabola with vertex (-3,-18) and y-intercept (0,0). Write your answer
1 answer:
Vertex form is
y = a(x - b)^2 + c
here a = -3 and b = -18 so we have
y = a(x + 3)^2 - 18
when x = 0 , y= 0 ( the y-intercept) so:-
0 = a(3^)2 - 18
9a = 18
a = 2
so the parabola is y = 2(x + 3)^2 - 18
x intercepts found as follows:-
2(x + 3)^2 - 18 = 0
(x + 3)^2 = 9
x + 3 = +/- sqrt9 = +/- 3
so x intercepts are 0 and -6 Answer
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