2 years ago

Can u plz help me with this

Mathematics

2 answers:

7nadin3 [17]2 years ago

8 0

Answer:

x = 61, y = 29

Step-by-step explanation:

29+x = 90

x = 61

x + y = 90

y + 61 = 90

y = 29

Studentka2010 [4]2 years ago

5 0

X=61
90-29=61
y=29
90-61=29

You might be interested in

NO LINKS I WILL REPORT!!! But help PLSS It's possible to build a triangle with side lengths of 5, 7, and 11.

strojnjashka [21]

Answer:

yes it is possible

I hope it's helps you

8 0

2 years ago

Read 2 more answers

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

2 years ago

Questions 1-6 please

MakcuM [25]

Question 1 is $6 \sqrt{2}$
question 2 is $4 \sqrt{5} + 3 \sqrt{2}$
question 3 is $6 \sqrt{2}$
question 4 is $8 \sqrt{3}$
question 5 is $\frac{ \sqrt{3}}{2}- \sqrt{3}$
question 6 is $5$