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Angelina_Jolie [31]
3 years ago
15

Explain how you can use a quick picture to find 3×2.7

Mathematics
2 answers:
Katen [24]3 years ago
6 0
5×2.7=13.5
7×2=35, carry the 3.
5×2=10, then add the 3 that was on top and then bring down the final result 13.
Once you've done that you have 135. Your final step is to move the decimal one place to the left which you then get 13.5.
Your final result is 13.5.
Hope this helped.

DanielleElmas [232]3 years ago
5 0
Here is an quick example <span>A "quick picture" is an estimate than? 5 x 2.7 ..... 5 x 3= 15 Its been a long time since elementary school and I do not remember "quick picture" The question was How can you use a "quick picture" to find 5 x 2.7? the answer is 13.5.......an estimate would be 15
dose this help?</span>
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Solving a Two-Step Matrix Equation<br> Solve the equation:
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Answer:

\boxed {x_{1} = 3}

\boxed {x_{2} = -4}

Step-by-step explanation:

Solve the following equation:

\left[\begin{array}{ccc}3&2\\5&5\\\end{array}\right] \left[\begin{array}{ccc}x_{1}\\x_{2}\\\end{array}\right] + \left[\begin{array}{ccc}1\\2\\\end{array}\right] = \left[\begin{array}{ccc}2\\-3\\\end{array}\right]

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-First equation:

3x_{1} + 2x_{2} + 1 = 2

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3x_{1} + 2x_{2} + 1 = 2

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3x_{1} + 2x_{2} + 1 - 1 = 2 - 1

3x_{1} + 2x_{2} = 1

-Subtract 2x_{2} to both sides:

3x_{1} + 2x_{2} - 2x_{2} = -2x_{2} + 1

3x_{1} = -2x_{2} + 1

-Divide both sides by 3:

3x_{1} = -2x_{2} + 1

x_{1} = \frac{1}{3} (-2x_{2} + 1)

-Multiply -2x_{2} + 1 by \frac{1}{3}:

x_{1} = \frac{1}{3} (-2x_{2} + 1)

x_{1} = -\frac{2}{3}x_{2} + \frac{1}{3}

-Substitute -\frac{2x_{2} + 1}{3} for x_{1} in the second equation, which is 5x_{1} + 5x_{2} + 2 = -3:

5x_{1} + 5x_{2} + 2 = -3

5(-\frac{2}{3}x_{2} + \frac{1}{3}) + 5x_{2} + 2 = -3

Multiply -\frac{2x_{2} + 1}{3} by 5:

5(-\frac{2}{3}x_{2} + \frac{1}{3}) + 5x_{2} + 2 = -3

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-Combine like terms:

-\frac{10}{3}x_{2} + \frac{5}{3} + 5x_{2} + 2 = -3

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-Subtract \frac{11}{3} to both sides:

\frac{5}{3}x_{2} + \frac{11}{3} - \frac{11}{3} = -3 - \frac{11}{3}

\frac{5}{3}x_{2} = -\frac{20}{3}

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\frac{\frac{5}{3}x_{2}}{\frac{5}{3}} = \frac{-\frac{20}{3}}{\frac{5}{3}}

\boxed {x_{2} = -4}

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x_{1} = -\frac{2}{3}(-4) + \frac{1}{3}

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Answer:

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Step-by-step explanation:

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Answer: Domain of function is R^{ + } or (0, \infty )

Step-by-step explanation:

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Therefore, Area of rectangle will be given function f(x)

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Here, It is important to notice that width and length of rectangle will always be positive values and also, area of rectangle is always positive.

we can write in equation as

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