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zhannawk [14.2K]
3 years ago
7

Simplify these -1/3 + -3/8 2.6 - (-1.5) (-2.8) divided by (-1.25)

Mathematics
1 answer:
sertanlavr [38]3 years ago
6 0

Answer:

(-1.25)(-1/3 - 3/8 2.6 + 1.5 - 2.8)

Step-by-step explanation:

From this point on it's easy

You might be interested in
Is 432 divisible by 9<br> I’m looking for the estimate 432 divided by 9
Monica [59]

Answer:

Yes (432 = 9 x48).

Step-by-step explanation:

The trick you need to know is the theorem that says that if the digits in a number add up to a multiple of 9, then the number itself is divisible by 9.

So we go 4+3+2 = 9.

So as this sum of 9 is divisible by 9, it means 432 is also divisible by 9.

If you want to work out the actual answer of 432 divided by 9, you can estimate it by doing 450 ÷ 9 = 50. Then see that 432 is 18 less than 450. And 18 = 2x9. So the answer to the division is 50-2 = 48.

5 0
3 years ago
United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n
Ivanshal [37]

Answer:

<u><em>a) The probability that exactly 4 flights are on time is equal to 0.0313</em></u>

<u><em></em></u>

<u><em>b) The probability that at most 3 flights are on time is equal to 0.0293</em></u>

<u><em></em></u>

<u><em>c) The probability that at least 8 flights are on time is equal to 0.00586</em></u>

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

<em>United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures. </em>

<em>a) The probability that exactly 4 flights are on time is = </em>

<em>b) The probability that at most 3 flights are on time is = </em>

<em>c)The probability that at least 8 flights are on time is =</em>

<h2>Solution to the problem</h2>

<u><em>a) Probability that exactly 4 flights are on time</em></u>

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

           P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}

Where _nC_x is the number of different combinations of x success in n trials.

            _nC_x=\frac{x!}{n!(n-x)!}

Hence,

            P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}

                                _9C_4=\frac{4!}{9!(9-4)!}=126

            P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125

<em><u>b) Probability that at most 3 flights are on time</u></em>

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

         P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)

P(X=0)=(0.5)^9=0.00195313 . . . (the probability that all are not on time)

P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625

P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125

P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625

P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\  P(X\leq 3) \approx 0.0293

<em><u>c) Probability that at least 8 flights are on time </u></em>

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

          P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586

6 0
4 years ago
NEED HELP LOTS OF POINTS!!! Diego had $21.32 and gave $9.50 to Elena. How much did he have left?
erastovalidia [21]

Answer:

11.18

Step by Step Explanation:

Subtract 9.5 from 21.23

8 0
3 years ago
Jeremy claims that if a linear function has a slope of the same steepness and the same y-intercept as the linear function in the
4vir4ik [10]

Answer: It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.

Step-by-step explanation:

Let us consider the general linear equation

Y = MX + C

On a coordinate plane, a line goes through points (0, negative 1) and (2, 0). 

Slope = ( 0 - -1)/( 2- 0) = 1/2

When x = 0, Y = -1

Substitutes both into general linear equation

-1 = 1/2(0) + C

C = -1

The equations for the coordinate is therefore

Y = 1/2X - 1

Let's check the equations one after the other

y = negative one-half x minus 1

Y = -1/2X - 1

y = negative one-half x + 1

Y = -1/2X + 1

y = one-half x minus 1

Y = 1/2X - 1

y = one-half x + 1

Y = 1/2X + 1

It is only the 3rd equation that is a good example to Jeremy's argument. Others are counter examples to Jeremy's argument.

7 0
3 years ago
Read 2 more answers
What are the solutions to the equation x² = 256?
Artyom0805 [142]
X = 16
x = - 16

You could do it this way
x^2 - 256 = 0
(x - 16)(x + 16) = 0
x - 16 = 0
x = 16

x + 16 = 0
x  = - 16

6 0
3 years ago
Read 2 more answers
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