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vivado [14]
3 years ago
9

Solve the following equations |3x-4(x+1)|=2

Mathematics
1 answer:
Lunna [17]3 years ago
3 0

Answer:

x = -6          or   x = -2

Step-by-step explanation:

|3x-4(x+1)|=2

Simplify inside the absolute value by distributing

|3x-4x-4|=2

Combine like terms

|-x-4|=2

Now separate into two equations, one positive and one negative

-x-4 = 2   or -x-4 = -2

Add 4 to each side

-x-4+4 = 2+4     or -x-4 = -2+4

-x = 6                  or -x =2

Multiply by -1

x = -6          or   x = -2

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Answer:

The greatest possible value of 3x - 2y is 20

Step-by-step explanation:

3x - 2y ------- 1

For getting the greatest possible value we must get the greatest value available, which is 10 and put it in place of x .

As 2y is being subtracted in the eq 1, we must put the smallest value available in the eq 1 to get the greatest possible result.

put x = 10 and y = 5 in eq 1

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What are the zeros of f(x)=(x-2)(3x+1)​
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Answer is 28 units because it’s 15 over 42 is equal to 10 over “x”, then you cross multiple which you end up with 15x=420 divide 420 from 15 which equals 28.
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