300.2 ° F
You can convert celcius to Fahrenheit using this formula
Mark brainliest please
<span><span><span><span><span>(<span>5+4</span>)</span><span>(2)</span></span>+6</span>−<span><span>(2)</span><span>(2)</span></span></span>−1</span><span>=<span><span><span><span><span>(9)</span><span>(2)</span></span>+6</span>−<span><span>(2)</span><span>(2)</span></span></span>−1</span></span><span>=<span><span><span>18+6</span>−<span><span>(2)</span><span>(2)</span></span></span>−1</span></span><span>=<span><span>24−<span><span>(2)</span><span>(2)</span></span></span>−1</span></span><span>=<span><span>24−4</span>−1</span></span><span>=<span>20−1</span></span><span>=<span>19</span></span>
Answer:
3/4
Step-by-step explanation:
2/3=8/12
3/4=9/12
Common denominator: 12
larger fraction: 3/4
PLS GIVE BRAINLIEST
73.

a)


b)
Since we can't divide by zero, we need to find when:

But before, we can factor the numerator and the denominator:

Now, we can conclude that the vertical asymptotes are located at:

so, for x = -3:


For x = 4:

Answer:
<em>The ball will roll upto </em><em>1 m.</em>
Step-by-step explanation:
A 1 kg ball has 10 joules of kinetic energy and starts to roll up a hill.
As along the hill the ball rises up, it loses its kinetic energy. The kinetic energy is converted to potential energy.
According to the law of conservation of energy, the kinetic energy plus the potential energy equals a constant.
Here given kinetic energy as 10 J, so this energy will get converted to potential energy.
We know that, potential energy is

where,
m is the mass, g is the acceleration due to gravity and h is the height.
Putting the values,


