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3 years ago

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Samantha withdrew $160 from her bank account.if the balance of the account is now 379.52 what was her balance before the withdra

w

1 answer:

zheka24 [161]3 years ago

3 0

Answer:

It was $539.52

Step-by-step explanation:

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A case in riverhead, new york, nine different crime victims listened to voice recordings of five different men. all nine victims

Alexus [3.1K]

the complete question in the attached figure

1) Find the probability that all nine victims would select the same person. You should enter your answer as a decimal, not as a percent. Do not round, as your answer should be a terminating decimal.

P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512

2) what is the probability that the first victim picks SOMEONE? ANYONE?

P=(1/5)=0.20 ---------------- > 20%

3) Now let’s look at victim #2. What is the probability that they pick the same person as victim #1?

P=(1/5)*(1/5)=0.04 --------------> 4%

4) Now let’s look at victim #3. What is the probability that they pick the same person as victim #1?

P=(1/5)*(1/5)*(1/5)=0.008 --------------> 0.8%

5) Now let's look at victim #9. What is the probability that they pick the same person as victim #1?

P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512

6) Once you find all those probabilities, what rule would apply?

the probability is given by (1/5)^n

n=number of victims that pick the same person---------> in this problem = 9

P=(1/5)^9= 0.000000512

5 0

3 years ago

PLEASE HURRY!!!!!!!!!!

valentinak56 [21]

Answer: 1/4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the volume of the triangular prism in the picture shown. Round your answer to the

Olenka [21]

Given:

A figure of a triangular prism.

Height of triangular base = $9\dfrac{2}{3}$ yd

Base of triangular base = 4 yd

Height of prism = 4 yd.

To find:

The volume of the triangular prism.

Solution:

Volume of a triangular prism is:

$V=Bh$ ...(i)

Where, B is the area of triangular base and h is the height of the prism.

Area of triangular base is:

$B=\dfrac{1}{2}\times base\times height$

$B=\dfrac{1}{2}\times 4\times 9\dfrac{2}{3}$

$B=2\times \dfrac{29}{3}$

$B=\dfrac{58}{3}$

Putting $B=\dfrac{58}{3}$ and h=4 in (i), we get

$V=\dfrac{58}{3}\times 4$

$V=\dfrac{232}{3}$

$V=77.33...$

$V\approx 77.3$

The volume of the triangular prism is 77.3 cubic yards. Therefore, the correct option is 2.

4 0

2 years ago

Help!!! The one marked red is wrong

kakasveta [241]

Answer:

4x+5

Step-by-step explanation:

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3 years ago

Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology ex

Nataly [62]

Answer:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion female for Biology

$\hat p_A =\frac{84199}{144796}=0.582$ represent the estimated proportion female for biology

$n_A=144796$ is the sample size for A

$p_B$ represent the real population proportion female for calculus AB

$\hat p_B =\frac{102598}{211693}=0.485$ represent the estimated proportion female for Calculus AB

$n_B=211693$ is the sample size required for B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942$

$(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978$

And the 90% confidence interval would be given (0.0942;0.09978).

We are confident at 90% that the difference between the two proportions is between $0.0942 \leq p_A -p_B \leq 0.09978$

5 0

3 years ago