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LekaFEV [45]
3 years ago
5

Vx-w=2 rearrange it and make x the subject

Mathematics
1 answer:
Anit [1.1K]3 years ago
8 0

Answer:

vx - w = 2 \\ vx = 2 + w \\  x =  \frac{2 + w}{v}

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20.3 is 4 times as large as some number. What is the number?
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What is the answer and how do you solve <br><br><br> 21x^3/3x^−1
Sunny_sXe [5.5K]

Answer:

  as written: 7x^2

  perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

  \dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2

___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

  21x^3/(3x^-1)

then the simplification is ...

  \dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4

_____

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^b/a^c = a^(b-c)

6 0
3 years ago
How to do this question plz answer ​
Soloha48 [4]

Answer:

(⌐■-■)

Step-by-step explanation:

Add perimeter of a quarter circle with radius 7 cm.

Hope this helps....

Have a nice day!!!!

3 0
3 years ago
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