Answer:
1800
Step-by-step explanation:
61 around to 60 and 29 rounds to 30. so
60 ×30=1800
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Answer:
x = 16
∠A = 39
∠B = 54
∠C = 87
Step-by-step explanation:
Make a equation of all of the angles added together is equal to 180 since the angles of a triangle added together is 180
(4x-10)+(2x+7)+(7x-25)=180
combine like terms
4x+2x+7x-10+7-25 = 180
13x-28=180
solve for x
13x=208
x = 16
plug in x to find the measure of the angle
∠A = 2(16) + 7 = 39
∠B = 4(16) - 10 = 54
∠C = 7(16) - 25 = 87
Add them together to double check your answer
39 + 54 + 87 = 180
hope this helps
TL;DR(too long didn't read): answer is 3/4
This question may look confusing, however, it is more easily understood once you see that the fractions appear to be changing more randomly than they are in a way you can recognize, however, they're not. Since they look like that it's because they're being multiplied by a fraction. Split the fractions into two to make it easier. 3/2 and 9/8, just look at them as '3' and '2' and '9' and '8'. 3 becomes 9. Which means either 6 was added or 3 was multiplied by 3. Compare to the next row, 27. 9-->27 can't be 6, so it's being multiplied by 3. Now for the bottom. 2 becomes 8, and knowing that the numerator of the fraction is being multiplied, so is the denominator then, so 2-->8 is 2 times 4. Put the numerator and denominator back together and you have 3/4. The answer is 3/4.
Answer:
B) To represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
Step-by-step explanation:
Here the point A is given as 3 on number line.
Point B is given as -5 on number line.
To find : IA-BI
The distance between any two point A and B is given as IA-BI.
Now, to find the absolute value:
IA-BI = I (3) - (-5)I
or, IA-BI = I (3) + 5I = I8I
= 8 units
or, IA-BI = 8 units
Hence, on the number line, the distance between -5 and 3 is 8 units.
And, to represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
