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3 years ago

What are two fractions equivalent to 12/14

Mathematics

2 answers:

Fiesta28 [93]3 years ago

8 0

Answer: Two fractions equivalent to 12/14 are:

6/7

24/28

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Step-by-step explanation:

6/7 is equivalent to 12/14 because:

12 ÷ 2 = 6

14 ÷ 2 = 7

There original fraction 12/14 was divided by 2 to get the new fraction of 6/7.

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24/28 is equivalent to 12/14 because:

12 x 2 = 24

14 x 2 = 28

The original fraction 12/14 was multiplied by 2 to get the new fraction of 24/28.

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, Hope this helps :)

Have a great day!!

Andrews [41]3 years ago

3 0

Hey there!

12/14

• BOTH NUMBERS HAVE THE COMMON FACTOR OF 2, SO WE CAN DIVIDE BOTH THE NUMERATOR (TOP number) FROM THE DENOMINATOR (BOTTOM number)

= 12 ÷ 2 / 14 ÷ 2

= 6/7

= 18/21

Therefore, your answer is: 6/7 or 18/21

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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3 years ago

Read 2 more answers

Please help me i'll mark u as brainiest if u get it right

Black_prince [1.1K]

Answer: a) 46 minutes
b) 10:47

The basic knowledge for this is that 60 minutes = 1 hour

a) Question a asks for how long it took from a 10:34 bus from Mosley to reach Bamford. From the table you can see that the 10:34 bus reaches Bamford at 11:20. All you have to do is count from 10:34 to 11:20.
10:34 will become 11:00 at 10:60 right? Clock's generally don't show 10:60 but goes directly to 11:00 after 1 minute is passed at 10:59. So from 10:34 to 11:00, it takes 26 minutes. Remember the bus reaches at 11:20 so from 11:00 to 11:20, it takes 20 minutes. Now add them up:
26 minutes + 20 minutes = 46 minutes

Here you go! Total 46 minutes from Mosley to Bamford.

b) From question b, we can see that Trina did not ride the first bus or by any chance missed it because the bus left at 10:14 and she is at the station at 10:15. Now think it from your perspective! You missed the first bus and you are in a big rush. So to reach your destination as early as possible, you will obviously take the next earliest bus. The next bus is at 10:24 (Belton). So if we take the 10:24 bus in Belton, it reaches at 10:47 in Garton.

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2 years ago

What is the solution to the system of equations? Use the substitution method to solve the system of equations. Show all of your

Luden [163]

Answer:

The solution would be (0, 5)

Step-by-step explanation:

In order to solve this system by substitution, simply take the value of y in the first equation and use it in place of y in the second. This will allow you to solve for x.

4x + 4y = 20

4x + 4(x + 5) = 20

4x + 4x + 20 = 20

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8x = 0

x = 0

Now that we have the value of x, we can find the value of y.

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y = 0 + 5

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4 years ago

A publisher of a newsmagazine has found through past experience that 60% of subscribers renew their subscriptions. In a random s

larisa86 [58]

Answer:

$z=\frac{0.57 -0.6}{\sqrt{\frac{0.6(1-0.6)}{100}}}=-0.612$

$p_v =2*P(z$

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X=57 represent the subscribers indicated that they planned to renew their subscriptions

$\hat p=\frac{57}{100}=0.57$ estimated proportion of subscribers indicated that they planned to renew their subscriptions

$p_o=0.6$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the current rate of renewals differs from the rate previously experienced, so the system of hypothesis are:

Null hypothesis: $p=0.6$

Alternative hypothesis: $p \neq 0.6$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.57 -0.6}{\sqrt{\frac{0.6(1-0.6)}{100}}}=-0.612$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

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3 years ago