1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ololo11 [35]
3 years ago
5

Y = -x + 4 , y = -3x + 16 . Answer as an ordered pair. (x,y)

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
7 0

Answer: Answer is (-3, 7)

Step-by-step explanation:

y = -x + 4 equ 1

y = 3x + 16 equ 2

Make x subject of formular in equ 1

x = 4 - y equ 3

Subatitute x = 4 - y in equ 2

y = 3(4-y) +16

y = 12 - 3y + 16

y + 3y = 12 + 16

4y = 28

y = 28/4 = 7

Substitute y = 7 in equ 1

7 = -x + 4

7 - 4 = -x

x = -3

Answer is (-3, 7)

Andrei [34K]3 years ago
4 0
Set them equal to each other. -x + 4 = -3x + 16 >>> (-x+3x)=(16-4) >>> 2x= 12 so x =6. Plug in x to an equation. Y= -(6) + 4 so y = -2. (6,-2) is the answer.
You might be interested in
Simplify (1/2)4. Plz answer fast
mr Goodwill [35]

Answer: 2

Step-by-step explanation: 1/2 x 4 = 4/2 = 2/1 = 2.

7 0
3 years ago
Please help me here dudes and dudettes
BabaBlast [244]

Answer:

what!!!!!!!!!!!!!!!!!! so only for dudesssssssss

6 0
3 years ago
The rate of change in the function y=x+4 is________ the rate of change of the function represented in the table.
Snezhnost [94]
Recall that the slope is the "average rate of change" of any function.

\bf y=\stackrel{slope}{1}x+4\qquad \qquad 
\begin{array}{ccll}
x&y\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
0&6\\2&8\\4&10\\6&12
\end{array}
\\\\\\
\textit{let's check what is the slope of the tabled function}\\
\textit{by using two points from it}

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 2}}\quad ,&{{ 8}})\quad 
%   (c,d)
&({{ 6}}\quad ,&{{ 12}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{12-8}{6-2}\implies \cfrac{4}{4}\implies 1
4 0
4 years ago
Read 2 more answers
2x2 - 4x –9 = 0<br> Completing the swuare
ASHA 777 [7]

Step-by-step explanation:

(a-b)^2=a^2-2ab+b^2\\\\2x^2-4x-9=0\qquad|\text{add 9 to both sides}\\\\2x^2-4x-9+9=0+9\\\\2x^2-4x=9\qquad|\text{divide both sides by 2}\\\\\dfrac{2x^2}{2}-\dfrac{4x}{2}=\dfrac{9}{2}\\\\x^2-2x=4.5\\\\x^2-2\cdot x\cdot1=4.5\qquad|\text{add}\ 1^2\ \text{to both sides}\\\\x^2-2\cdot x\cdot1+1^2=4.5+1^2\\\\(x-1)^2=5.5\iff x-1=\pm\sqrt{5.5}\qquad|\text{add 1 to both sides}\\\\x=1-\sqrt{5.5}\ \vee\ x=1+\sqrt{5.5}

4 0
3 years ago
Write 0.05 as a fraction. A) 1 12 B) 1 15 Eliminate C) 1 18 D) 1 9
zheka24 [161]

x=0.0\overline{5}\\\\x=0.0555...\qquad\text{multiply both sides by 10}\\\\10x=0.555...\qquad\text{multiply both sides by 10}\\\\100x=5.555...\\\\\text{Make the difference:}\\\\100x-10x=5.555...-0.555...\\\\90x=5\qquad\text{divide both sides by 90}\\\\x=\dfrac{5}{90}\\\\x=\dfrac{5:5}{90:5}\\\\x=\dfrac{1}{18}\\\\Answer:\ \boxed{0.0\overline{5}=\dfrac{1}{18}}\to\boxed{C)}

6 0
3 years ago
Other questions:
  • WILL MAKE BRAINLIEST!!
    15·2 answers
  • Prove that if b is a square matrix then b+b^t is symmetric
    5·1 answer
  • Sharifa's white ball rolled 143 centimeters in 4 seconds and her green ball rolled 112 centimeters in 3 seconds. Which ball roll
    7·1 answer
  • I need help pls❗❗❗Its complicated ​
    14·1 answer
  • The point is rotated 180 degrees using as the center. Explain why the image must lie on the ray. I need
    8·1 answer
  • Which inverse trig function could I use to solve this problem?
    13·1 answer
  • Can anyone pls sub to my youttube? Its called Yakobu, It would rlly help. :)
    8·1 answer
  • Slow and steady wins the race. The leatherback sea turtle is the fastest known reptile, with a maximum speed of 21.9221.9221, po
    7·2 answers
  • I need help ty-math-
    5·2 answers
  • The base of a square prism has an area of 16 in.2 The
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!