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3 years ago

10

Magsanay sa paggamit ng iskala.Alamin ang tunay na distansya sa paggamit ng iskala.Sagutin ang mga sumusunod. Isulat ang sagot s

a sagutang papel

Advanced Placement (AP)

1 answer:

STALIN [3.7K]3 years ago

6 0

Answer:

Anong iskala panoto lang bayan?

Asan ang tanong ?di ko maintindihan...

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Answer:

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Explanation:

You probably already know the point slope equation:

y = m(x - x₀) + y₀

All you need is the slope and the (x₀, y₀).

The (x₀, y₀) could be solved by plugging in the given x=-1 value into the function.

m, the slope, is the same as a derivative; ie. a derivative is a slope.

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3 years ago

May someone help me solve d and e.

omeli [17]

Answer:

d.

$x = 2 {y}^{2} - 4 \\ 2 {y}^{2} = x + 4 \\ \\ {y}^{2} = \frac{x + 4}{2} \\ \\ y = \frac{ + }{} \sqrt{ \frac{x + 4}{2} } \\ \\ y = \frac{ + }{} \frac{ \sqrt{x + 4} }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} } \\ \\ y = \frac{ + }{} \: \frac{ \sqrt{x + 4} \times \sqrt{2} }{ \sqrt{2} \sqrt{2} } \\ \\ y = \frac{ + }{} \frac{ \sqrt{2(x + 4)} }{2} \\ \\ y =\frac{ \sqrt{2(x + 4)} }{2} \\ \\ y = - \frac{ \sqrt{2(x + 4)} }{2}$

e.

$x = {(y - 5)}^{2}$

with the root of both sides

$\sqrt{x} = \sqrt{ {(y - 5)}^{2} } \\ \\ \frac{ + }{} \sqrt{x} = y - 5 \\ \\ y = \sqrt{x} + 5 \\ y = - \sqrt{x} + 5$

I hope I helped you^_^

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Use that one thing. what’s a DVOM?

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