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2 years ago

1. The sum of the real numbers x and y is 15. Their

Mathematics

1 answer:

Brut [27]2 years ago

6 0

Answer:

x = 9

y = 6

Step-by-step explanation:

Let's set up equations:

x + y = 15

x - y = 3

Let's rearrange one of these equations to use the substitution method:

x - y = 3

Add y to each side:

x = y + 3

Substitute in for x:

x + y = 15

y + 3 + y = 15

Combine like terms:

( y + y ) + 3 = 15

2y + 3 = 15

Subtract 3 from each side:

2y = 12

Divide each side by 2:

y = 6

Substitute this in to find the other variable:

x + y = 15

x + 6 = 15

Subtract 6 from each side:

x = 9

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Need help on this!! Will give 20 points!!!

mezya [45]

Your first step should be to plug in the q and f values they give you. q being 20 and f being 16. From there you want to isolate 1/p by subtracting the 1/20 from both sides. You should be left with 1/p = 1/16 - 1/20. This will come out to be 1/80 or 0.0125. Now that one side is 1/p and the other is 1/80 you can multiply both sides by p in order to get 1=1/80 times p which means that p = 80 . Hope this helps

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2 years ago

Read 2 more answers

3x+7-6=(8/7)-0<br>Value of x?

ArbitrLikvidat [17]

Answer:

$\boxed{\sf x = \dfrac{1}{21}}$

Explanation:

$\rightarrow \sf 3x+7-6= \dfrac{8}{7} - 0$

simplify the following

$\rightarrow \sf 3x+1= \dfrac{8}{7}$

subtract 1 from both sides

$\rightarrow \sf 3x+ 1 -1= \dfrac{8}{7} - 1$

simplify the following

$\rightarrow \sf 3x= \dfrac{1}{7}$

multiply both sides by 1/3

$\rightarrow \sf 3x \cdot \dfrac{1}{3}= \dfrac{1}{7}\cdot \dfrac{1}{3}$

simplify the following

$\rightarrow \sf x = \dfrac{1}{21}$

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2 years ago

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Question 10 pls help

Ivenika [448]

Answer:

Step-by-step explanation:

3 0

3 years ago

If anyone could help?

Trava [24]

Answer:

$y=\frac{5}{7}x$ and $y=\frac{7}{9}x$

Step-by-step explanation:

A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.

In $y=\frac{5}{7}x$ when x=3, y=15/4≈2.14

In $y=\frac{3}{5}x$ when x=3, y=1.8

In $y=\frac{7}{9}x$ when x=3, y≈2.33

In $y=\frac{7}{11}x$ when x=3, y≈1.90

We can observe that in two cases, $y=\frac{5}{7}x$ and $y=\frac{7}{9}x$ , y is greater than 2.

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3 years ago

Which graph best represents the relationship between time and the average mass?

natita [175]

The second graph or the letter B

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3 years ago