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azamat
3 years ago
14

What is value of 6x6x6x6x6x6x6=6x

Mathematics
2 answers:
pychu [463]3 years ago
8 0

Answer:

46656

Step-by-step explanation:

6x6x6x6x6x6x6 can be written in its index form as 6⁷

6x = 6⁷

6x = 279936

Applying change of subject formula, divide both sides of the equation by 6

6x/6 = 279936/6

x = 46656

Naily [24]3 years ago
5 0

Answer:

6x6x6x6x6x6x6=6x

279 936=6x

x=46 656

Step-by-step explanation:

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DochEvi [55]

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Step-by-step explanation:

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2 years ago
Find dx/dt when y=2 and dy/dt=1, given that x^4=8y^5-240<br><br> dx/dt=
katrin2010 [14]

Answer:

The value of \frac{dx}{dt} is \frac{160}{x^3}.

Step-by-step explanation:

The given equation is

x^4=8y^5-240

We need to find the value of \frac{dx}{dt}.

Differentiate with respect to t.

4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0              [\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]

4x^3\frac{dx}{dt}=40y^4\frac{dy}{dt}

It is given that y=2 and dy/dt=1, substitute these values in the above equation.

4x^3\frac{dx}{dt}=40(2)^4(1)

4x^3\frac{dx}{dt}=40(16)(1)

4x^3\frac{dx}{dt}=640

Divide both sides by 4x³.

\frac{dx}{dt}=\frac{640}{4x^3}

\frac{dx}{dt}=\frac{160}{x^3}

Therefore the value of \frac{dx}{dt} is \frac{160}{x^3}.

4 0
3 years ago
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