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Marysya12 [62]
3 years ago
12

Help me plz, thanks.

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
5 0
6/20 chance or simplified would be 3/10. Answer [D] is correct.
kotykmax [81]3 years ago
4 0
Answer : 3/10

There is 6 blue marbles and 20 marbles into total. 

6/10 simplified is 3/10
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Is the trinomial a perfect square? write yes or no. x^2+12x+36
Lapatulllka [165]

Answer:

no

Step-by-step explanation:

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3 years ago
If g(x)=−3x+9 g ( x ) = − 3 x + 9 and f(x)=2x+7 f ( x ) = 2 x + 7 , what is the value of g(f(x)) g ( f ( x ) ) ?
olya-2409 [2.1K]
G(f(x)) = g(2x +7) = -3(2x +7) +9 = -6x -21 +9

g(f(x)) = -6x -12
5 0
3 years ago
Write in slope intercept form an equation of the line that passes through(-4,1), (4,3)
saul85 [17]

Answer:

Step-by-step explanation:

I know this is not your question but it may help

Question:Write an equation in Slope intercept form of the line that passes through the given  points (-3,4) (1,4)

2 Answers:

1: y=x+4

2:

answer would be “y=4”

to find the answer: first you have to find the slope with the given points. (y2 - y1 / x2 - x1)

plug it in to get: (4-4 / 1- -3) = 0/4 = 0

this means the slope would be 0

if the y intercepts are the same then it usually indicates that the slope would be 0 and that the answer is the y intercept.. but if you don’t understand how to get slope-intercept using other coordinates then here’s how:

you can use point-slope formula (y-y1 = m (x-x1) in order to do this just plug in one of the coordinates. in this case an example of point-slope form would be:

y-4 = 0 (x - -3) or y-4 = 0(x-1)

it doesn’t matter which coordinates you use..

then solve the point slope for slope-intercept.

y-4 = 0(x-3) multiply 0 with x and -3

y-4 = 0x move -4 to the right by adding 4

y = 0x + 4 or y = 4 would be your answer!

7 0
2 years ago
Which explanation provides the best real-world senario of the graph​
VikaD [51]

Answer:

i don't know

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers​
lidiya [134]

Answer:

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

Step-by-step explanation:

We are given x=\sqrt{3}-1 and we are asked to find the value of x^2-x+1.

So we will need to find x^2.

x=\sqrt{3}-1

Square both sides:

x^2=(\sqrt{3}-1)^2

Expand using identity: (x-a)^2=x^2-2ax+a^2.

x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2

x^2=3-2\sqrt{3}+1

x^2=4-2\sqrt{3}

Let's go back to the full x^2-x+1.

x^2-x+1

(4-2\sqrt{3})-(\sqrt{3}-1)+1

4-2\sqrt{3}-\sqrt{3}+1+1

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

5 0
4 years ago
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