9514 1404 393
Answer:
3a by 4a
Step-by-step explanation:
For dimensions L and W, the area and perimeter are ...
A = LW = 12a^2
P = 2(L+W) = 14a
Using the second equation, we can find L:
L +W = 7a . . . . . divide by 2
L = 7a -W
Substituting into the area formula gives the quadratic ...
(7a -W)(W) = 12a^2
W^2 -7aW +12a^2 = 0 . . . . arrange in standard form
(W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)
Then we have the two solutions ...
W = 3a, L = 4a
W = 4a, L = 3a
The rectangle dimensions are 3a by 4a.
The series 1022,1032,1042,1052....
a1=a=1022
d=a2-a1=1032-1022=10
n=5 as 5th term
Sn= a+(n-1)d
= 1022+(5-1)10
= 1022+40
= 1062
Next house will have 1062 as number.
HELLO THERE!
(:
This is a problem that looks harder then it seems, First determine the cost of each item he is trying to buy. Then figure out the number of dollars he has to spend. Once you have figured that out you divide the cost into how much he has.
For example.
John has 10 dollars. He wants to buy pencils. Each pencil will cost john 2 Dollars. How many can he buy?
By dividing the cost of the pencils = 2 into the number of dollars he has 10 Divided by 2, we get 5.
Now it's your turn. Divide the number he has to spend by the price of the items. This will get you your answer!
Hope this helped!
