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3 years ago

Given that f(x) = x^2– 5x– 36 and g(x) = x + 4, find (f +9)(x) and express

Mathematics

2 answers:

kkurt [141]3 years ago

8 0

Answer:

x^2 -4x-32

Step-by-step explanation:

f(x) = x^2– 5x– 36

g(x) = x + 4

(f +g)(x) = x^2– 5x– 36 + x + 4

Combine like terms

= x^2 -4x-32

olasank [31]3 years ago

6 0

Answer:

$\longmapsto \: f(x) = {x}^{2} - 5x - 36 \\ \longmapsto \: g(x) = x + 4 \\ \longmapsto(f + g)(x) \\ = f(x) + g(x) \\ = ( {x}^{2} - 5x - 36) + (x + 4) \\ = {x}^{2} - 5x - 36 + x + 4 \\ = \boxed{ {x}^{2} - 4x - 32}$

<u>x²-4x-32 (in standard form)</u> is the right answer.

You might be interested in

The function f(x) = 6x + 8 is transformed to function g through a horizontal stretch by a factor of 5. What is the equation of f

elixir [45]

Answer:

$g(x) = 30\cdot x +40$ ; $a \approx 1.898$ , $k = 40$ .

Step-by-step explanation:

The resultant function is obtained by multiplying $f(x)$ by a real number $k$ . That is:

$g(x) = k \cdot f (x)$

If $k = 5$ and $f(x) = 6\cdot x + 8$ , then $g(x)$ is:

$g(x) = 5\cdot (6\cdot x + 8)$

$g(x) = 30\cdot x +40$

Given that presence of the expression $g(x) = 6^{a}\cdot x + k$ , then:

$6^{a} = 30$ and $k = 40$

The value of a is obtained by applying the definition of logarithms:

$a = \log_{6}30$

$a \approx 1.898$

Finally, the value of k is found by direct comparison:

$k = 40$

6 0

3 years ago

1. spotlight is placed 25 feet from a flag that is 20 feet high Spotlight Which expression can be used to find the angle of elev

Ganezh [65]

Answer:

Im not entirely sure this is right but

0 = tan^-1(20 ÷ 25)

0 ≈ 38.65°

hope i helped lol

5 0

3 years ago

Suppose you read online that children first count to 10 successfully when they are 32 months old, on average. You perform a hypo

creativ13 [48]

Answer:

$p_v =2*P(t_{(35)}$

Step-by-step explanation:

Assuming this info from R

hist(gifted$count)

## Min. 1st Qu. Median Mean 3rd Qu. Max.

## 21.00 28.00 31.00 30.69 34.25 39.00

## Sd

## [1] 4.314887

Data given and notation

$\bar X=30.69$ represent the mean

$s=4.3149$ represent the sample standard deviation

$n=36$ sample size

$\mu_o =32$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is different than 32, the system of hypothesis would be:

Null hypothesis: $\mu = 32$

Alternative hypothesis: $\mu \neq 32$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{30.69-32}{\frac{4.3149}{\sqrt{36}}}=-1.822$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=36-1=35$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(35)}$

7 0

3 years ago

*Pleaase help*

Evgen [1.6K]

Answer:

s=7w + 85..$141 in total for 8 weeks

8 0

3 years ago

Use the diagram to find lengths. BP is the perpendicular bisector of AC. QC is the

faust18 [17]

Answer:

The length of the side PC is 34 cm.

Step-by-step explanation:

We are given that BP is the perpendicular bisector of AC. QC is the perpendicular bisector of BD. AB = BC = CD.

Suppose BP = 16 cm and AD = 90 cm.

As, it is given that AD = 90 cm and the three sides AB = BC = CD.

From the figure it is clear that AD = AB + BC + CD

So, AB = $\frac{90}{3}$ = 30 cm

BC = $\frac{90}{3}$ = 30 cm

CD = $\frac{90}{3}$ = 30 cm

Since the triangle, BPC is a right-angled triangle as $\angle$ PBC = 90°, so we can use Pythagoras theorem in this triangle to find the length of the side PC.