I know for a fact that 1, 2 and 4 are correct. I'm almost positive 3 and 5 are right too
1. B
2.D
3.D
4.B
5.D
Length of segment of the hypotenuse adjacent to the shorter leg is 5 inches and the length of the altitude is 3 inches.
Step-by-step explanation:
Step 1: Let the triangle be ΔABC with right angle at B. The altitude drawn from B intersects the hypotenuse AC at D. So 2 new right angled triangles are formed, ΔADB and ΔCDB.
Step 2: According to a theorem in similarity of triangles, when an altitude is drawn from any angle to the hypotenuse of a right triangle, the 2 newly formed triangles are similar to each other as well as to the bigger right triangle. So ΔABC ~ ΔADB ~ ΔCDB.
Step 3: Identify the corresponding sides and form an equation based on proportion. Let the length of the altitude be x. Considering ΔABC and ΔADB, AB/DB = AC/AB
⇒ 6/x = 12/6
⇒ 6/x = 2
⇒ x = 3 inches
Step 4: To find length of the hypotenuse adjacent to the shorter leg (side AB of 6 inches), consider ΔADB.
⇒ 
⇒
⇒
⇒
⇒
⇒AD = 5 inches
Answer:
a³ - a² - 3a+ 6
Step-by-step explanation:
we are asked by how much does (a³-2a) exceed (a²+a-6)
in other words, we are being asked to find the difference between the 2 terms above.
Mathematically we are asked to find:
(a³-2a) - (a²+a-6) (expand parentheses by distribution property)
=(a³-2a - a²- a + 6)
= a³ - a² - 3a+ 6 (answer)
Answer:
I'm quite sure that the answer is b - 5/6b + 1 5/6
Hope this helps! Please mark brainliest! Have a great day!
Use the formula for simple interest:
i = p* r* t
Here, $120 = $2000*r* (18/12 years)
$120
Then r = ------------------ = 0.04. That's 4% per year.
$2000(1.5)