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klio [65]
3 years ago
13

Help me plzzzzzzzzzzz

Mathematics
2 answers:
Brrunno [24]3 years ago
8 0

Answer:

i know the answer it is the second one dude if i am wrong sorry

Step-by-step explanation:

horrorfan [7]3 years ago
3 0

Answer:

<u>x = 11/3</u>

Step-by-step explanation:

This is because that if you plug it in,

√x+3 = 2√x-2

√11/3 + 3 = 2√11/3 - 2

√20/3 = 2√5/3

Statement is true, therefore <u>x = 11/3</u>.

Hope this helps!

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Answer:

12:00

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5 0
3 years ago
Please help asap this is really important
Neporo4naja [7]

Answer:y=2x+2

Step-by-step explanation:

click on calculator.net. All you have to do is put in the coordinates and it will give you the slope and it will put it into slope intercept form.

8 0
3 years ago
Read 2 more answers
G find the domain for the particular solution to the differential equation dy dx equals the quotient of negative 1 times x and y
faust18 [17]
\frac{dy}{dx} = \frac{-x}{y}
by separating the variables
∴ y dy = -x dx
integrating both sides with respect to x
∴ ∫y dy = ∫-x dx
∴ \frac{ y^{2} }{2} = - \frac{ x^{2} }{2} +c
finding c using initial condition y(2) = 2.
∴ \frac{ 2^{2} }{2} = - \frac{ 2^{2} }{2} +c
∴ c = 4
 ∴ \frac{ y^{2} }{2} = - \frac{ x^{2} }{2} +4
multiplying all the equation by 2
∴ y² = -x² + 8
∴ x² + y² = 8
The resultant equation represents the equation of the circle
with center (0,0)  and radius = √8 = 2√2
so, the domain of this function is [-2√2 , 2√2]
See the attached figure



7 0
3 years ago
Please help me please​
lbvjy [14]
60 because area of a rectangle is l*b*w. So 6*2*5 will equal 60
6 0
2 years ago
17. Write the equation of a line that is perpendicular to the given line and that passes through the given point.
nataly862011 [7]

\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\\text{We have the line in point-slope form:}\\\\y-y_1=m(x-x_1)\\\\m-slope\\\\y-2=\dfrac{7}{3}(x+5)\to m_1=\dfrac{7}{3}\\\\\text{therefore}\ m_2=-\dfrac{1}{\frac{7}{3}}=-\dfrac{3}{7}.\\\\\text{We have the slope}\ m=-\dfrac{3}{7}\ \text{and the point}\ (-4,\ 9).\ \text{Substitute:}\\\\y-9=-\dfrac{3}{7}(x-4))\\\\\boxed{y-9=-\dfrac{3}{7}(x+4)}

7 0
3 years ago
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