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klio [65]
2 years ago
13

Help me plzzzzzzzzzzz

Mathematics
2 answers:
Brrunno [24]2 years ago
8 0

Answer:

i know the answer it is the second one dude if i am wrong sorry

Step-by-step explanation:

horrorfan [7]2 years ago
3 0

Answer:

<u>x = 11/3</u>

Step-by-step explanation:

This is because that if you plug it in,

√x+3 = 2√x-2

√11/3 + 3 = 2√11/3 - 2

√20/3 = 2√5/3

Statement is true, therefore <u>x = 11/3</u>.

Hope this helps!

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The opposite corners of a quadrilateral are right angles. The quadrilateral is not a rhombus. What kind of quadrilateral is this
tatiyna
A rhombus is a 4 sided shape with equal lengths. Even though it has equal lengths, it has opposite sides that are parallel, and angles that are equal. It also has diaginols (dashed lines) meat in the middle
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=12%20%5Cfrac%7B1%7D%7B3%7D%20%5Cdiv%202" id="TexFormula1" title="12 \frac{1}{3} \div 2" alt="1
aev [14]

Answer:

37/6

Step-by-step explanation:

Simplify the following:

(12 + 1/3)/2

Put 12 + 1/3 over the common denominator 3. 12 + 1/3 = (3×12)/3 + 1/3:

((3×12)/3 + 1/3)/2

3×12 = 36:

(36/3 + 1/3)/2

36/3 + 1/3 = (36 + 1)/3:

((36 + 1)/3)/2

36 + 1 = 37:

(37/3)/2

37/3×1/2 = 37/(3×2):

37/(3×2)

3×2 = 6:

Answer: 37/6

3 0
3 years ago
Is 1|3 and 3|3 are equal ?
netineya [11]
No, they aren't. 3/3+ 1 whole
3 0
3 years ago
Read 2 more answers
Which of the following has a graph that is a straight line? (4 points) Equation 4: y = 3x3 Equation 3: y = 2x2 + 4 Equation 1: y
Ray Of Light [21]
The equation of the line: y = mx + b.

Therefore your answer is Equation 1: y = 2x + 7.
3 0
3 years ago
Read 2 more answers
What is the solution set of x2 + 5x + 1 = 0?
DerKrebs [107]

Answer:

\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}

Step-by-step explanation:

x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}

\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}

3 0
3 years ago
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