Answer:
y^2 - 5y - 4
Step-by-step explanation:
So you want f(y) such that
(y^2-5y+1) - f(y) = 5
Subtract both sides by (y^2-5y+1):
-f(y) = 5 - (y^2-5y+1)
-f(y) = -y^2 + 5y + 4
f(y) = y^2 - 5y - 4
So the polynomial you are looking for is y^2 - 5y - 4
Answer:
(1,-4)
Step-by-step explanation:
-5+1=-4
3+-2=1
A^2 +b^2 = c^2
a= wall
b = ground (18)
c = ladder (25)
a^2 + 18^2 = 25^2
a^2 + 324 = 625
a^2 = 301
a = 17.349
First we have to find the slope by dividing the difference of the ys over the xs
-6 - 3 = -9 (y)
2 - -4 = 6 (x)
the slope is -9/6 or -3/2
now we plug the slop along with a set of points into the slope intercept formula (y=mx+b) to find b (the y intercept)
-6 = 2(-3/2) + b
-6 = -3 + b
-3 = b
so the equation would be y = (-3/2)x - 3
