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2 years ago

How many different 11-letter words (real or imaginary) can be formed from the letters in the word PROBABILITY?

Mathematics

1 answer:

Lostsunrise [7]2 years ago

6 0

<h3>Answer: 9,979,200</h3>

This is one single number. It's just a bit under 10 million

Delete the commas if necessary.

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Explanation:

If we could tell the repeated letters apart, then there would be

11*10*9*8*7*6*5*4*3*2*1 = 39,916,800

different ways to scramble up the letters.

However, we have 2 copies of b and 2 copies of i

So we have to divide by 2*2 = 4 to correct this overcounting

(39,916,800)/4 = 9,979,200

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natka813 [3]

Answer:

30 blue pins

Step-by-step explanation:

30% is the same as 30 out of 100, so this can be written in this fraction: $\frac{30}{100}$

now, you should multiply this fraction by the total number of pins she ordered:

100 x $\frac{30}{100}$

to solve this, you can simplify by dividing 100 by 100, this equals 1

30 times 1 is 30

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Answer:

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Step-by-step explanation:

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2 years ago

156 times 0.20 times 6

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Step-by-step explanation:

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3 years ago

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Hunter did not want to spend more than 150$ for a flight from Reno to Los Angeles. Write the inequality that models this situati

Jobisdone [24]

Answer:

$(a)\ x < 150$

$(b)\ x = 149; x = 148$

Step-by-step explanation:

Given

$Amount = 150$ --- not more than

$x \to$ spending

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Not more than means <

So, the inequality is:

$Spending < Amount$

$x < 150$

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2 years ago

A toy manufacturer wants to know how many new toys children buy each year. A sample of 305 children was taken to study their pur

Harrizon [31]

Answer:

The 80% confidence interval for the mean number of toys purchased each year is between 7.5 and 7.7 toys.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.8}{2} = 0.1$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.1 = 0.9$ , so Z = 1.28.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.28\frac{1.5}{\sqrt{305}} = 0.1$

The lower end of the interval is the sample mean subtracted by M. So it is 7.6 - 0.1 = 7.5

The upper end of the interval is the sample mean added to M. So it is 7.6 + 0.1 = 7.7

The 80% confidence interval for the mean number of toys purchased each year is between 7.5 and 7.7 toys.

8 0

3 years ago