Answer:
Simplest form of radical √245c³ = 7c√5c
Step-by-step explanation:
Given radical value:
√245c³
Find:
Simplest form of radical √245c³
Computation:
Given value
√245c³
Step 1 :
Prime factorisation of given radical value
Simplest form of radical √245c³ = √5 × 7 × 7 × c × c × c
By taking 7 and c from out of root
Simplest form of radical √245c³ = 7 × c √ 5 × c
Simplest form of radical √245c³ = 7c√5c
A polynomial has real coeffients
a polynomial with roots b and c and d can be.factored into the form
f(x)=a(x-b)(x-c)(x-c)
and each of those terms can be raised to any positive power
if it has real coeffients and.one of the roots is a+bi (compex number) then a-bi is also root
ok, so since 2+3i is a root, 2-3i is also a root
the function can bex
f(x)=a(x-2)(x-1)(x-(2+3i))(x-(2-3i))
where a can be any real number except 0
expand it yourself to get the polynomial because it's hard to type nyubers on mobile
note that i=√-1 so i^2=-1
Answer:
y= -5
Step-by-step explanation:
2 and one half hours is how much time it will take
please can i have a brainliest
X + x + 2 + x + 4 = 429 where x is the smallest number.
3x + 6 = 429
3x = 429 - 6 = 423
x = 423/3 = 141
The largest number is 141 + 4 = 145 Answer