Answer:
$45
Step-by-step explanation:
Here we need to calculate the income of this year.
We know that a year has 52 weeks. And, our payed weeks are 51, they are, the 50 weeks we work plus the one week of paid-vacation. The remaining week does not give us income, as is unpaid. So our total year income is:
51 * $615 = $31,365
So, our surplus will be our income minus our expenses:
Surplus = $31,365 - $31,320 = $45
Our cash surplus is $45
Let x=number 1 let y=number2
there sum is equal to 70
then
number1+number2=70
substituting
x+y=70
y=70-x
let there product will be p
p=xy
substituting
p=x(70-x)
which is choice c
The total money spent for the Dinner and Dessert is $22 so to figure out how much was spent on the taxi ride you're going to want to subtract $22 from $31 (31 = x + 22) or (31 - 22 = x).
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
