Answer:
AB = x+ 8
Step-by-step explanation:
Given : QS=6x and CS=5x-8
From the given figure,
QS = QC + CS
We are given with QS and CS
Replace it the above equation
6x = QC + 5x -8
Solve for QC
Subtract 5x on both sides
x = QC + -8
Add 8 on both sodes
QC= x + 8
QABC is a rectangle
QC = AB
So AB = x+ 8
Answer:
Here you go.Hope this help!!
Answer:
B.
R (2,4)
soln
center(h,k)=(6,1)
radius (r)=5units
so
eqn of circle is (x-6)^2+(y-1)^2=5^2
2 2
or, 25=x +y -12x-2y+36+1 now , only the given point (6,1)satisfies the eqn so this point lies on circle
Answer:
<h2>
512 m²</h2>
Step-by-step explanation:
The surface area is a sum of areas of four triangles with base of <em>8 m</em> and hight of <em>12 m</em> and areas of five squares with sides of <em>8 m.</em>
<em />
<h3>
Sa = 4×¹/₂×8×12 + 5×8² = 192 + 320 = 512 m²</h3>