Answer: (-2,8); (-6,0)
Step-by-step explanation:
y=mx+b
m=slope
slope=y2-y1/x2-x1
so m=2
y=2x+b
8×9=72
5×8=40
So the answer is 8
Given:
Sample size, n = 40
Sample mean, xb = $6.88
Population std. deviation, σ = $1.92 (known)
Confidence interval = 90%
Assume normal distribution for the population.
The confidence interval is
(xb + 1.645*(σ/√n), xb - 1.645*(σ/√n)
= (6.88 + (1.645*1.92)/√40, 6.88 - (1.645*1.92)/√40)
= (7.38, 6.38)
Answer: The 90% confidence interval is (7.38, 6.38)
Answer:
To calculate the mean of a set of data, you have to work out the sum of the data (in this case, you need to work out the sum of all the points) and divide it by the number of data points there are (in this case, number of games played).
So you have to do:
(67 + 45 + 84 + 55 + 73 + 36 + 80 + 62 + 38)/9 = 60
The mean number of points is 60.
Step-by-step explanation:
please mark as brainiest
Answer:
0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Find the probability that he weighs between 170 and 220 pounds.
This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.
X = 220



has a pvalue of 0.6554
X = 170



has a pvalue of 0.2743
0.6554 - 0.2743 = 0.3811
0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.