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TiliK225 [7]
3 years ago
7

Subject - MathsNeed help!​

Mathematics
2 answers:
8090 [49]3 years ago
7 0

Step-by-step explanation:

1. \: (c) \: 25 \% \\ 2. \: (b) \: 25\% \\ 3. \: (d) \: 1750 \:  \\ 4. \: (c) \: 108 \\ 5. \: (a) \: 20\% \\ 6. \: (a) \: 2400 \\ 7. \: (b) \: 10 \\ 8. \: (c) \: 24 \\ 9. \: (c) \:  \frac{1}{25}  \\ 10. \: (a) \: x/y = constant

xeze [42]3 years ago
5 0

1) 25%

2) 60

3) 1750

4)

5) 20%

6) 2400

7) 10

8)24

9) 1/25

10) X/y = constant.

sorry 4 no. is not taught in Nepal

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Answer:

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The probability for the ball to fall into the green ball in one roll is 2/1919+2 = 2/40 = 1/20. The probability for the ball to roll into other color is, therefore, 19/20.

For 25 rolls, the probability for the ball to never fall into the green color is obteined by powering 19/20 25 times, hence it is 19/20^25 = 0.2773

To obtain the probability of the ball to fall once into the green color, we need to multiply 1/20 by 19/20 powered 24 times, and then multiply by 25 (this corresponds on the total possible positions for the green roll). The result is 1/20* (19/20)^24 *25 = 0.3649

The exercise is asking us the probability for the ball to fall into the green color at least twice. We can calculate it by substracting from 1 the probability of the complementary event: the event in which the ball falls only once or 0 times. That probability is obtained from summing the disjoint events: the probability for the ball falling once and the probability of the ball never falling. We alredy computed those probabilities.

As a result. The probability that the ball falls into the green slot at least twice is 1- 0.2773-0.3629 = 0.3576

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