Yes, of course.
When you replace people with technologically advanced robots, it can disturb the economic factors. Although I don't agree with using robots as an every day, common thing, such as self-driving cars or like in the question, using robots as doctors. Technology is technology, it will always need updates and sometimes they break down or need repairs, so that could provide jobs for people; tech jobs that is. Not everybody is tech savvy though, but you learn. I still don't agree with it, but it is what it is.
D)Exhaustion
Hope this helps
Answer:
int main()
{
int A1= {5,3,4,8,9,0,7};
int SArri1 = sizeof(A1);
printf("Original array: ");
for (int i=0; i < SArri1;i++)
printf("", A1[i] );
int i, sum = 20, n= 0;
printf("\nArray pairs whose sum equal to 20: ");
for (int i=0; i<SArri1; i++)
for (int j=i+1; j<SArri1; j++)
if (A1[i]+A1[j] == sum)
{
Printf(“\n”, array1[i])
Printf(“,”,array1[j]);
n++;
}
printf("\nNumber of pairs whose sum equal to 20: ",n)
return 0;
}
Explanation:
First of all, you should create the array of integers, and put random numbers. Then you have to save in a constant the size of the array (in this code is called SArr1) With a for you can print all the numbers that are on the array because then you will print all array pairs whose sum is equal to a specified numer. in this code we are going to use 20.
then with a condition (if) you are going to compare one of number of the array with all the others and check if its equal to 20. If yes, it going to print the numbers that answer to that condition and it's going to add +1 to the variable n (for this you will need to use two bucles for)
Then you can print the number of pairs whose sum is equal to 20 by printing n
You wouldhave to do it on your phone to screen shot it