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2 years ago

In the equation 4x² - 16x + 12 = 0, the solution is?

Mathematics

2 answers:

sergij07 [2.7K]2 years ago

8 0

Answer:

Step-by-step explanation:

${4x}^{2} - 16x + 12 = 0 \\ {4x}^{2} - 4x - 12x + 12 = 0 \\ 4x(x - 1) - 12(x - 1) = 0 \\ (4x - 12)(x - 1) = 0 \\$

(4x - 12) = 0 or (x - 1) = 0

$(4x - 12) = 0 \\ 4x - 12 = 0 \\ 4x = 0 + 12 \\ 4x = 12 \\x = \frac{12}{4} \\ x = 3 \\$

$(x - 1) = 0 \\ x - 1 = 0 \\ x = 0 + 1 \\ x = 1$

x = 3 or x = 1 should be.

ElenaW [278]2 years ago

5 0

X= 3, 1

Hope this helps<3

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A certain circle can be represented by the following equation. x^2+y^2+18x+14y+105=0 What is the center of the circle? What is t

Gre4nikov [31]

Answer:

See below.

Step-by-step explanation:

Recall the equation for a circle:

$(x-h)^2+(y-k)^2=r^2$ , where (h,k) is the center and r is the radius.

We need to turn the given equation into the above format. We do this by completing the square.

First, group them:

$(x^2+18x)+(y^2+14y)=-105$

For the first section, complete the square for $x^2+18x$ :

$x^2+18x+81-81$

$(x+9)^2-81$

Do the same for the second:

$y^2+14y$

$y^2+14y+49-49$

$(y+7)^2-49$

All together:

$((x+9)^2-81)+((y+7)^2-49)=-105$

$(x+9)^2+(y+7)^2-130=-105$

$(x+9)^2+(y+7)^2=25$

The center is (-9,-7).

The radius is $\sqrt{25}=5$

5 0

2 years ago

Evaluate this question

cestrela7 [59]

Answer:

Step-by-step explanation:

$\bigg( \frac{16}{49} \bigg)^{ - \frac{3}{2} } \\ \\ = \bigg( \frac{49}{16} \bigg)^{ \frac{3}{2} } \\ \\ = \bigg( \frac{ {7}^{2} }{ {4}^{2} } \bigg)^{ \frac{3}{2} } \\ \\ = \bigg( \frac{ {7}}{ {4} } \bigg)^{ \frac{2 \times 3}{2} } \\ \\ = \bigg( \frac{ {7}}{ {4} } \bigg)^{ 3} \\ \\ = \frac{343}{64} \\$