Question

In the equation 4x² - 16x + 12 = 0, the solution is?​

Answer 1

Answer:

x = 3 or x = 1

Step-by-step explanation:

${4x}^{2} - 16x + 12 = 0 \\ {4x}^{2} - 4x - 12x + 12 = 0 \\ 4x(x - 1) - 12(x - 1) = 0 \\ (4x - 12)(x - 1) = 0$

(4x - 12) = 0 or (x - 1) = 0

$(4x - 12) = 0 \\ 4x - 12 = 0 \\ 4x = 0 + 12 \\ 4x = 12 \\x = \frac{12}{4} \\ x = 3$

$(x - 1) = 0 \\ x - 1 = 0 \\ x = 0 + 1 \\ x = 1$

x = 3 or x = 1 should be.

Answer 2

X= 3, 1



Hope this helps<3