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3 years ago

Pleaseee helpppp asaappppb:((((

Mathematics

1 answer:

VikaD [51]3 years ago

5 0

Answer:

5.) •Response

6.) • Experimental unit

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4/x-1+6/x+1=-12/x^2-1

Mademuasel [1]

$\frac{4}{x - 1} + \frac{6}{x + 1} = \frac{-12}{x^{2} - 1}$

$\frac{4(x + 1)}{(x - 1)(x + 1)} + \frac{6(x - 1)}{(x - 1)(x + 1)} = \frac{-12}{x^{2} - 1}$

$\frac{4x + 4}{x^{2} - 1} + \frac{6x - 6}{x^{2} - 1} = \frac{-12}{x^{2} - 1}$

$\frac{10x - 2}{x^{2} - 1} = \frac{-12}{x^{2} - 1}$

$(10x - 2)(x^{2} - 1) = -12(x^{2} - 1)$
$10x^{3} - 10x^{2} - 2x^{2} + 2 = -12(x^{2}) + 12(1)$
$10x^{3} - 12x^{2} + 2 = -12x^{2} + 12$
$10x^{3} - 12x^{2} + 12x^{2} + 2 = -12x^{2} + 12x^{2} + 12$
$10x^{3} + 2 - 2 = 12 - 2$
$\frac{10x^{3}}{10} = \frac{10}{10}$

$x^{3} = 1$
$x = 1$

4 0

2 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Aleksandr [31]

Answer:

Step-by-step explanation:

8 0

2 years ago

Write equation in standard form y-1= -1/4(x-6)

const2013 [10]

The standard form:

$Ax+By=C$

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$y-1=-\dfrac{1}{4}(x-6)$ use distributive property

$y-1=-\dfrac{1}{4}x+\dfrac{3}{2}$ multiply both sides by 8

$8y-8=-2x+4\cdot3$

$8y-8=-2x+12$ add 2x to both sides

$2x+8y-8=12$ add 8 to both sides

$\boxed{2x+8y=20}$

6 0

2 years ago

Twice the sum of j and 4

beks73 [17]

Answer:

J+4*2

Step-by-step explanation:

4 0

3 years ago

How many and of which kind of roots does the equation f(x)=x^3+2x^2+4x+8 have?

ss7ja [257]

The cubic equation f(x) = x³ + 2 · x² + 4 · x + 8 has one real root and two complex roots.

<h3>What kind of roots does have a cubic equation? </h3>

In this problem we have a cubic equation and the nature of their roots must be inferred according to a algebraic method.

Cubic equations are polynomials of the form y = a · x³ + b · x² + c · x + d, there is a method to infer the nature of the roots of such polynomials: The discriminant from Cardano's method, an analytical method used to solve polynomials of the form a · x³ + b · x² + c · x + d = 0.

The discriminant is described below:

Δ = 18 · a · b · c · d - 4 · b³ · d + b² · c² - 4 · a · c³ - 27 · a² · d² (1)

Where:

There are three distinct real roots for Δ > 0.
Real roots with multiplicity greater than 1 for Δ = 0.
A real root and two complex roots for Δ < 0.

If we know that a = 1, b = 2, c = 4 and d = 8, then the nature of the roots is:

Δ = 18 · 1 · 2 · 4 · 8 - 4 · 2³ · 8 + 2² · 4² - 4 · 1 · 4³ - 27 · 1² · 8²

Δ = - 1024

The cubic equation f(x) = x³ + 2 · x² + 4 · x + 8 has one real root and two complex roots.

To learn more on cubic equations: brainly.com/question/13730904

#SPJ1

4 0

2 years ago