Answer:
Unicode
Explanation:
This is a fairly large code and Is well known throughout my family since we study ancient codex and modern codes to solve crimes and find relics of the past, although our research has proven good and unicode is one that is being studied currently now, I have found it as long and very time consuming. Although ASCII is a computer code that consists of graphs and numbers it actually shortens the text. and hexadecimal has been proven to be less reliable and binary is a short code with little symbols
Answer:
DiffServ
Explanation:
The IP QoS which is fully known as QUALITY OF SERVICE mechanism that involves prioritizing traffic is DIFFERENTIATED SERVICES (DiffServ).
DIFFERENTIATED SERVICES help to differentiate ,arrange ,manage, control and focus on network traffic that are of great significance or important first before network that are less important or by their order of importance in order to provide quality of service and to avoid network traffic congestion which may want to reduce the quality of service when their is to much load on the network .
That would be a star network. A star network isn't necessarily shaped like a star, of course, but like you mention this topology has a central device, usually a server of some sorts, and then many different endpoints coming out of that central device, such as the client computers for the server.
Answer:
The solution code is written in Python 3
- firstStr = input("Enter first string: ")
- secondStr = input("Enter second string: ")
-
- if(firstStr < secondStr):
- print("The first string comes first alphabetically.")
- elif(firstStr > secondStr):
- print("The second string comes first alphabetically.")
- else:
- print("The first and second string are same")
Explanation:
Firstly, prompt the user to input two strings (Line 1 - 2).
Next create if else if statement to check if the firstStr is less than, greater than or equal to the secondStr and then print the appropriate message accordingly (Line 4- 9). For example, the program display message "The first string comes first alphabetically." if it find the firstStr is less than secondStr.
