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lukranit [14]
2 years ago
15

Can you give a step by step explanation for this problem?

Mathematics
1 answer:
Rus_ich [418]2 years ago
7 0

Answer:

choose the first

Step-by-step explanation:

When h=0, T is the highest (because the temperature is highest at noon)

And knowing that the temperature difference in the world cannot exceed 60 degrees in a day, only the first choice is common sense.

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Find the area and round to the nearest hundredth??
bagirrra123 [75]

Answer:

total area = 193.31 m²

Step-by-step explanation:

rectangle area = 7 x 15 = 105 m²

semi circle area = (3.14)(7.5²)/2 = 88.31 m²

total area = 105 m² + 88.31 m² = 193.31 m²

8 0
2 years ago
PLZ HElP!!! Simplify 10 – 3x – 13 + 5x 3 – 3x 1 2x – 3 3 – 2x
777dan777 [17]

the answer to the first part is 2x-3

4 0
3 years ago
I WILL GIVE BRAINLIEST!!! PLZ HELP ASAP!!!
Fed [463]

Answer:

C

Step-by-step explanation:

Calculate the distance using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = E(- 2, 2) and (x₂, y₂ ) = F(4, - 6)

EF = \sqrt{(4+2)^2+(-6-2)^2}

    = \sqrt{6^2+(-8)^2}

    = \sqrt{36+64}

    = \sqrt{100} = 10 → C

7 0
2 years ago
Read 2 more answers
Erin is making fruit salad.For each bowl of fruit salad,she needs 2/3 cup of strawberries.How many cups will she use if she make
grigory [225]
She needs 18 times of 2/3 cup, this is

18\cdot \frac{2}{3}=12 cups
5 0
3 years ago
Read 2 more answers
Martin is cleaning the tires of his bicycle. He notices that his bicycle tire has a radius of 8 inches. How much bigger is the a
algol [13]

Strange question, as normally we would not calculate the "area of the tire." A tire has a cross-sectional area, true, but we don't know the outside radius of the tire when it's mounted on the wheel.

We could certainly calculate the area of a circle with radius 8 inches; it's

A = πr^2, or (here) A = π (8 in)^2 = 64π in^2.

The circumference of the wheel (of radius 8 in) is C = 2π*r, or 16π in.

The numerical difference between 64π and 16π is 48π; this makes no sense because we cannot compare area (in^2) to length (in).

If possible, discuss this situatio with your teacher.



8 0
2 years ago
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