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3 years ago

Please could I have some help with this question? Thanks

Mathematics

2 answers:

Sveta_85 [38]3 years ago

5 0

Answer: 270

Step-by-step explanation:

1) Find DE

1 : 6

17 : x

Cross multiply

x = 17 * 6

x = 102

DE = 102

2) Compare the two triangles

1st (ABC)

side = 45

base = 17

2nd (ADE)

side = x

base = 102

$\frac{x}{45} = \frac{102}{17}$

Cross multiply

17x = 102 x 45

17x = 4590

x = 4590/17

x = 270

AD = 270

rosijanka [135]3 years ago

4 0

270

Mark brainliest please

Hope this helps

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The test statistics that is an appropriate hypothesis test is $z =\frac{0.35 - 0.40}{\sqrt{\frac{0.35(1 - 0.35)}{60} + \frac{0.40(1 - 0.40)}{85}}}$

<h3>How to determine the test statistic</h3>

<u>40 milligrams of medication</u>

Patients = 60

Lower stress level patients = 21

The mean of this medication is:

$\bar x = \frac{x}{n}$

So, we have:

$\bar x_1 = \frac{21}{60}$

$\bar x_1 = 0.35$

<u>75 milligrams of medication</u>

Patients = 85

Lower stress level patients = 34

The mean of this medication is:

$\bar x = \frac{x}{n}$

So, we have:

$\bar x_2 = \frac{34}{85}$

$\bar x_2 =0.4$

The test statistic is then calculated as:

$z =\frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\bar x_1(1 - \bar x_1)}{n_1} + \frac{\bar x_2(1 - \bar x_2)}{n_2}}}$

The equation becomes

$z =\frac{0.35 - 0.40}{\sqrt{\frac{0.35(1 - 0.35)}{60} + \frac{0.40(1 - 0.40)}{85}}}$

Hence, the test statistics that is an appropriate hypothesis test is $z =\frac{0.35 - 0.40}{\sqrt{\frac{0.35(1 - 0.35)}{60} + \frac{0.40(1 - 0.40)}{85}}}$

Please could I have some help with this question? Thanks ​

Please could I have some help with this question? Thanks