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pashok25 [27]
3 years ago
6

What is the equation in slope-intercept form of the line

Mathematics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

y = (-4/3)x + 4  

Step-by-step explanation:

Let y = mx + b, be the equation of the line in slope intercept form where we need to find m and b.

Perpendicular to y = (3/4)x - 5, means that m = - (1 / (3/4) ) = - 4/3

So, at this point, y = (-4/3)x + b.

Crossing the x - axis at 3 means that (3, 0) is a point on the line, where we note that x=3 and y=0.

Thus, we plug in these values into the equation y = (-4/3)x + b, to get

0 = (-4/3)(3) + b

0 = -4 + b, so that

b = 4.

Hence, the answer is:

y = (-4/3)x + 4

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Answer:

Step-by-step explanation:Given  that

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3 years ago
What is one tenth of this expanded number
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3 years ago
Bill and George go target shooting together. Both shoot at atarget at the same time. Suppose Bill hits the target withprobabilit
german

Answer: (a) \frac{2}{9}       (b) \frac{6}{41}

Step-by-step explanation:

(a) P( Bill hitting the target) = 0.7        P( Bill not hitting the target) = 0.3

    P( George hitting the target) = 0.4     P(George not hitting the target) = 0.6

Now the chances that exactly one shot hit the target is = 0.7 x 0.6 + 0.4 x 0.3

                                                                                            = 0.54

Chances that George hit the target is = 0.4 x 0.3 = 0.12

So given that exactly one shot hit the target, probability that it was George's shot = \frac{0.12}{0.54} = \frac{2}{9} .

(b) The numerator in the second part would be the same as of (a) part which is 0.12.

The change in the denominator will be that now we know that the target is hit so now in denominator we include the chance of both hitting the target at same time that is 0.4 x 0.7 and the rest of the equation is same as above i.e.

Given that the target is hit,probability that George hit it =                                                 \frac{0.4\times 0.3}{0.7\times 0.6 +0.4\times 0.3+0.4\times 0.7}  = = \frac{6}{41}                                                                        

                                                                                           

6 0
3 years ago
The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0). Which type of triangle is ∆ABC? Select All that apply.
stepan [7]

Given:

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0).

To find:

The type of the given triangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(5-(-3))^2+(8-2)^2}

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And,

AC=\sqrt{(11-(-3))^2+(0-2)^2}

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Using the Pythagoras theorem, we can say that the given triangle is a right triangle.

Therefore, the correct options are B and F.

7 0
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