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Anastasy [175]
3 years ago
7

Suppose you invest $400 at an annual interest rate of 7.6% compounded continuously. How much will you have in the account after

1.5 years? Round the solution to the nearest dollar.
Mathematics
1 answer:
likoan [24]3 years ago
6 0
\bf ~~~~~~ \textit{Compounding Continuosly Interest Earned Amount}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$400\\
r=rate\to 7.6\%\to \frac{7.6}{100}\to &0.076\\
t=years\to &1.5
\end{cases}
\\\\\\
A=400e^{0.076\cdot 1.5}\implies A=400e^{0.114}
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Answer:

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Step-by-step explanation:

=> Total amount the 1st year = 90,000

=> Since after the 1st yr, there was a reduction of 4%, so 100% - 4% = 96% or 0.96

=> Total time = 6

We know that the formula of a geometric sequence is;

aₙ = a₁ * r⁽ⁿ⁻¹⁾

In which;

  • aₙ = the value that has to be figured out (in this case it would be a₆)
  • a₁ = the first term of the sequence (in this case it would be 90,000)
  • r = common ration (in this case it would be 0.96)
  • n = given time (in this case it would be 6)

Therefore we can finally say;

=> aₙ = a₁ * r⁽ⁿ⁻¹⁾

=> a₆ = 90,000 * 0.96⁶⁻¹

=> a₆ = 90,000 * 0.96⁵

=> a₆ = 73383.54

=> a₆ = 73384 (Rounded to the nearest whole number)

Therefore, rounding the answer to the nearest whole number, the answer would be; 73384 kilotons

Hope this helps! (Btw big shout out to jcherry99 for helping me figure this out!!)

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MEDIAN:
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MEAN:
(12 + 16 + 10 + 9 + 20 + 11 + 20) / 7 = 14

RANGE:
Highest value: 20
Lowest value: 9
Range: 20 - 9 = 11

INTERQUARTILE RANGE:
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Third quartile: 11 (It is between 20 and 20)
Interquartile range: 16 - 11 = 5

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Answer:

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therefore ⅙ for each person.

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