Find the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function: y=4x^2-8x-3

Help please and thank you

Stells [14]

Answer:

1

Cans 4cans 8 cans 12 cans

Cost $2.25 $4.5 $6.75

2

Ice Cream 180 q 360 q 540 q 720q 900q 1080 q

Hours 2 hours 4 hours 6 hours 8 hours 10 hours 12 hours

***q = quarts

3

Distance 650 miles 1300 miles 1950 miles

Hours 3 hours 6 hours 9 hours

8 0

2 years ago

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Simplify and reduce to the lowest terms.<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B-7%7D%7B12%7D%20" id="TexFormula1" t

Paladinen [302]

When you divide two fractions, you're actually multiplying one of them by the reciprocal of the other. First, find the reciprocal of the second fraction by flipping it upside down. Then, multiply it by the first fraction. (Numerator x numerator and denominator x denominator)

$\frac{-7}{12}$ ÷ $\frac{2}{3}$ Replace the second fraction with it's reciprocal
$\frac{-7}{12}$ x $\frac{3}{2}$ Multiply (-7 x 3 and 12 x 2)
$\frac{-21}{24}$ Both 21 and 24 are divisible by three, so divide them by 3
$\frac{-7}{8}$

6 0

3 years ago

Sixth grade

Nikolay [14]

The answer is 12n + 3

3 0

3 years ago

Okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

masya89 [10]

Answer:

okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

Step-by-step explanation:

thannnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnks forrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr thhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhe frrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrree poinnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnts

6 0

2 years ago

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Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br

Serggg [28]

Answer:

dA/dt = 12 - 2A/(100 + t)

Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

R_in is the rate at which salt enters

R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

So, after t minutes, there will be (100 + t) gallons in the tank

Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

So, we substitute the values of R_in and R_out into the Differential equation to get;

dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

5 0

3 years ago