All categories

3 years ago

Whats the greatest common factor of 18 and 27 and 54

Mathematics

2 answers:

vodomira [7]3 years ago

7 0

Answer: 9

Step-by-step explanation:

From doing the math I think it should be 9

NemiM [27]3 years ago

6 0

Start with the smallest number, 18:

The factors of 18 are: 1, 2, 3, 6, 9, 18.

So the GCF for all three must be one of those.

Now consider the next smallest number. Of the factors of 18, only these are also factors of 27:

1, 3, 9

Now consider the last number, 54. Of the remaining factors, 9 is the greatest and 9 goes into 54.

The GCF is 9.

By starting with the smallest number, you usually limit how many factors you'll ever need to consider.

You might be interested in

Two trains going in opposite directions leave at the same time. Train B travels 30 mph faster than train A. In 5 hours the train

Angelina_Jolie [31]

Answer:

Step-by-step explanation:because

3 0

3 years ago

Ken said that he is going to reduce the number of calories that he eats during the day. Ken's trainer asked him to start off sma

abruzzese [7]

2.200 or 2,200????????????

4 0

3 years ago

Write 1 16 as a decimal. A) 0.00625 B) 0.0625 C) 0.625 D) 6.25

xenn [34]

Answer:

b) 0.0625

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ

sattari [20]

<h3>Explanation:</h3>

Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).

cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)

(1 -sin^2(θ))cot^2(θ) = . . . . . replace cos^2 with 1-sin^2

cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin

cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=81-%28y-1%29%28y%5E2%2B27%29%20%5Cgeq%200%20%5C%5C%5C%5C%2081-%28y%5E3%2B27y-y%5E2-27%29%20%5C

Zarrin [17]

First thing you'll need to know is that the value for this equation is actually an approximation 'and' it is imaginary, so, one method is via brute force method.

You let f(y) equals to that equation, then, find the values for f(y) using values from y=-5 to 5, you just substitute the values in you'll get -393,-296,-225,... till when y=3 is f(y)=-9; y=4 is f(y)=48, so there is a change in signs when 'y' went from y=3 to y=4, the answer is between 3 and 4, you can work out a little bit deeper using 3.1, 3.2... You get the point. The value is close to 3.1818...

The other method is using Newton's method, it is similar to this but with a twist because it involves differentiation, so $y_{n+1}=y_n-\frac{f(y)}{f'(y)}$ where 'n' is the number you approximate, like n=0,1,2... etc. f(y) would the equation, and f'(y) is the derivative of f(y), now what you'll need to do is substitute the 'n' values into 'y' to find the approximation.

7 0

3 years ago