The central angle of a circle measures 108° and intercepts an arc of 6π inches.

The area of a circle is 153.86 square meters. What is the diameter of the circle? Use 3.14 for π.

iren2701 [21]

Answer:

14m

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

153.86 = 3.14 r^2

Divide each side by 3.14

153.86 /3.14 = r^2

49 = r^2

Take the square root of each side

sqrt(49) = sqrt(r^2)

7 = r

We want the diameter which is twice the radius

d = 2r

d =2*7

d =14

5 0

3 years ago

In each box, 20% of the total candies are grape flavored.

mrs_skeptik [129]

Answer:

9

Step-by-step explanation:

20 x 5 = 100

45/5 = 9

9 to 20 = 11

45 to 100 = 55

<u>55</u> = 5<--- Linear

11

(since the total answer is linear, the answer is right)

6 0

3 years ago

Read 2 more answers

If a polynomial function f(x)has root -2 + square root 8 and 9 what must be a factor of f(x)

Rasek [7]

Answer:

$(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)$

Step-by-step explanation:

Given that f(x) is a polynomial function.

This implies that f(x) has x terms of positive integral degrees and also rational coefficients only.

Since an irrational root is given a root of f(x), we find that its conjugate also should be a root of f(x)

i.e. If $-2+\sqrt{8}$ is a root, then $-2-\sqrt{8}$ is also a root.

(Because this only when multiplied will make coefficients rational)

So the factors of f(x) should be atleast

$(x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)$

There can be other factors also but this is compulsory

7 0

3 years ago

A rectangle swimming pool is 8 feet deep. One side of the pool is 4.5 times longer than the other. The amount of water needed fo

wel

The side lengths of the pool 10 ft and 45 ft.

<u>SOLUTION: </u>

Given, a rectangle swimming pool is 8 feet deep.

One side of the pool is 4.5 times longer than the other.

Let the length of pool be n feet, the width will be 4.5n feet

The amount of water needed for the swimming pool is 3600 cubic ft

We have to find the dimensions of the pool. Now, we know that,

$\begin{array}{l}{\text {volume of pool}=\text {depth} \times \text {length } \times \text {width}} \\\\ {\rightarrow 3600 \text { cubic } f t=8 \text { feet } \times \text { n feet } \times(4.5 n) \text { feet }} \\\\ {\rightarrow 8 n \times 4.5 n=3600} \\\\ {\rightarrow 36 n^{2}=3600} \\\\ {\rightarrow n^{2}=100}\end{array}$