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3 years ago

Solve. 23x+56=313 Enter your answer as a mixed number in simplest form in the box.

Mathematics

2 answers:

Sladkaya [172]3 years ago

7 0

Answer:

11 4/23

Step-by-step explanation:

$23x+56=313\\\\23x +56 -56 = 313-56\\\\23x = 257\\\\23x \div 23 = 257 \div 23\\\\x = \dfrac{257}{23} = 11 \dfrac{4}{23}$

Anastaziya [24]3 years ago

5 0

Answer:

x = 11 $\frac{4}{23}$

Step-by-step explanation:

23x + 56 = 313

23x = 257

x = 11 $\frac{4}{23}$

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Where do the bottom go

Leni [432]

Answer:

b=2a-1= 2

b=5a+2= 3

b=8a=1

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3 years ago

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SOVA2 [1]

Answer:

Step-by-step explanation:

= $5\sqrt{20}$

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3 years ago

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2