Answer:
B. cosθ ≠ 0
Step-by-step explanation:
As we notice, tanθ is a fraction. Fractions are undefined when the denominator is equal to or approaching 0 because one cannot divide by zero. Thus, the denominator in this case is cosθ, and therefore it cannot equal zero for the equation to be true.
You first switch f(x) with x in this equation
<span>x=<span>1<span>9f(x)−2</span></span></span>
Then you solve for f(x).
<span>9f(x)−2=<span>1x</span></span>
<span>9f(x)=<span>1x</span>+2</span>
<span>f(x)=<span>1<span>/9x</span></span>+<span>2/9</span></span>
Then you simply repalace f(x) with f^-1(x)
It will look like this
<span><span>f−</span>1(x)=<span>1<span>/9x</span></span>+<span>2/<span>9
Hope i could help
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Answer
What is the question?
Explanation
Thanks for the free points
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The easiest way is a successive division by 4:
1st division: 2032/4 = 508 and 0 (0 is the 1st Remaining)
2nd division 508/4 = 127 and 0 (0 is the 2nd Remaining)
3rd division 127/4 = 31 and 3 (3 is the 3rd Remaining)
4th division 31/4 = 7 and 3 (3, is the 4th Remaining)
5th division 7/4 = 1 and 3 (3 is the 5th Remaining)
Now you write the last quotient (the 5th) , that is 1 and add to it all remaining starting from the 5th , backward to the 1st remaining,
133300