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Naddika [18.5K]
3 years ago
7

5x= 20 word problem

Mathematics
2 answers:
madam [21]3 years ago
6 0

\mapsto \rm \: 5x = 20

\mapsto \rm \: x =   \cancel\frac{20}{5}  \\

\red \mapsto \ \boxed{ \rm \red { = 4}}

gtnhenbr [62]3 years ago
4 0

{{ \large{ \blue{ \rm{{↬}}}}}} \large \rm \: \:   5x \:  =  \: 20

{{ \large{ \blue{ \rm{{↬}}}}}} \large \rm \: \:   x \:  =  \:   \cancel\frac{20}{5}  \\

{{ \large{ \blue{ \rm{{↬}}}}}} \large \rm \: \:   x \:  =  \: 4

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1. if 50 people pay $50 a month for their cellphone bill how much money is it?
Murljashka [212]
1) 50*50, our 2500
2) 1500
3)1500
4) 900

just multiply t the number of people by the amount each pays
5 0
3 years ago
Michelle can fold 4 baskets of clothes in 54 minutes, while Ruby can fold 4 baskets of clothes in 108 minutes. How long will it
padilas [110]
Michelle can fold 4/54 baskets per minute = 8/108 baskets per minute.
Ruby can fold 4/108 baskets per minute.

Each minute Michelle and Ruby work together, they can fold
   8/108 +4/108 = 12/108 = 1/9
of a basket of clothes. For 8 baskets of clothes, it will take them
   (8 baskets)/(1/9 baskets/minute) = 72 minutes
3 0
3 years ago
What is the missing numerator? blank over five plus eighteen over twenty equals thirty over twenty 8 5 3 2
Oliga [24]

Given:

\dfrac{?}{5}+\dfrac{18}{20}=\dfrac{30}{20}

To find:

The missing value.

Solution:

Let x be the missing value.

We have,

\dfrac{x}{5}+\dfrac{18}{20}=\dfrac{30}{20}

\dfrac{x}{5}+\dfrac{9}{10}=\dfrac{3}{2}

Subtract \dfrac{9}{10} from both sides.

\dfrac{x}{5}=\dfrac{3}{2}-\dfrac{9}{10}

\dfrac{x}{5}=\dfrac{15-9}{10}

\dfrac{x}{5}=\dfrac{6}{10}

\dfrac{x}{5}=\dfrac{3}{5}

Multiplying both sides by 5, we get

x=3

So, the missing value is 3.

Therefore, the correct option is C.

8 0
3 years ago
PLEASE I NEED THE ANSWER DON'T IGNORE MY QUESTION!!!
kenny6666 [7]

Answer:

x=7.8

Step-by-step explanation:

take 49 degree as reference angle

using cos rule

cos 49=adjacent/hypotenuse

0.65=x/12

0.65*12=x

7.8=x

3 0
3 years ago
Read 2 more answers
Which expressions are polynomials?
igor_vitrenko [27]

Option A: z + 1

Option B: 6 + w

Option D: 2 x^{4}-y

Solution:

Let us first define the polynomial.

A polynomial can have constants, variables, exponents and fractional coefficients.

A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.

<u>To find which expressions are polynomial:</u>

Option A: z + 1

By the definition, z + 1 is a polynomial.

It is polynomial.

Option B: 6 + w

By the definition, 6 + w is a polynomial.

It is polynomial.

Option C: y^{2}-\sqrt[3]{y}+4

y^{2}-\sqrt[3]{y}+4=y^{2}-{y}^{1/3}+4

Here, y have fractional exponent.

So, it is not a polynomial.

Option D: 2 x^{4}-y

By the definition, 2 x^{4}-y is a polynomial.

It is polynomial.

Hence z + 1, 6 +w and 2 x^{4}-y are polynomials.

6 0
4 years ago
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