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3 years ago

13

Can someone explain how to do this from step by step in order to get marked.

1 answer:

ivanzaharov [21]3 years ago

4 0

Step-by-step explanation:

First, convert the mixed fraction into an improper fraction:

$1\dfrac{2}{5} = \dfrac{7}{5}$

Rewrite 2 as 2/1 and then cross-multiply to combine:

$\dfrac{2}{1} - \dfrac{7}{5} = \dfrac{(2)(5) - (7)(1)}{(1)(5)} = \dfrac{10 - 7}{5} = \dfrac{3}{5}$

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If x varies inversely as the square of y and if x=3 when y=-1, what is the value of x when y =3

lyudmila [28]

Answer:

$x$ would be $(1/3)$ when $y = 3$ .

Step-by-step explanation:

The question states that $x$ varies "inversely" as $y^2$ . In other words, there is a non-zero number $a$ (a constant) such that:

$\displaystyle x = \frac{a}{y^2}$ .

The challenging part is to find the value of $a$ in this equation.

Given that $x = 3$ when $y = -1$ , replace the $x$ in this equation with $3$ and $y$ with $(-1)$ . This equation should still be valid:

$\displaystyle 3 = \frac{a}{(-1)^{2}}$ .

Solve for $a$ :

$a = 3 \times (-1)^2 = 3$ .

Hence, the relation between $x$ and $y$ becomes:

$\displaystyle x = \frac{3}{y^2}$ .

Find the value of $x$ when $y = 3$ by replacing the $y$ in this equation with $3$ .

$\displaystyle x = \frac{3}{3^2} = \frac{1}{3}$ .

In other words, the value of $x$ would be $\displaystyle \frac{1}{3}$ when $y = 3$ .

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3 years ago

HELP ASAP!! Identify the least common multiple of x^2 + 7x + 6 and x^2 − 3x − 4.

vesna_86 [32]

(x+1)(x+6)(x-4)

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

Hope This Helps & Good Luck

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4 years ago

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Leni [432]

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3 years ago

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