Answer:
3 also could be said as 3/1
Step-by-step explanation:
To solve this first find the area of each of the white shapes inside the rectangle
The formula for the area of a circle is:
A = πr²
In this case we know that the radius is 2
Plug what you know into the area of a circle formula:
A = π2²
A = π4
A = 4π
A ≈ 12.57
The formula for the area of a square is:
A = Length x Height
In this case we know that both length and height are 3
Plug what you know into the formula for area of a square:
A = 3 x 3
A = 9
To find the area of the UNSHADED region simply add together the area of the circle (12.57) with the area of the square (9):
12.57 + 9 ≈ 21.57
To find the area of the SHADED region find the total area of the surrounding rectangle then subtract the area of unshaded area from the total area of the surrounding rectangle.
The formula for the area of a rectangle is:
A = Length x Height
The length is 10 and the height is 7
A = 10 x 7
A = 70
Shaded region:
70 - 21.57 = 48.43
Unshaded region: 21.57
Total area of surrounding rectangle: 70
Shaded region: 48.43
Hope this helped!
~Just a girl in love with Shawn Mendes
I think it’s either C or D
Answer:
The length and width of another rectangular field with same perimeter but a larger area is 80 m by 70 m
Step-by-step explanation:
The perimeter of the existing field is
2(l + b)
= 2(90 + 60) = 2(150) = 300 yards
So we want another field having the same perimeter but a larger area
The area we have here is 90 * 60 = 5,400 square yards
If we had 80 by 70
Perimeter will still be 2(70 + 80) = 150
But the area will be 80 * 70 = 5,600 square yards
Answer:
look at the photo
Step-by-step explanation:
Since the inequality is already written in y=mx+b, you can easily graph the line. +3 is the y intercept, so one point would be (0,3). -2 resembles the slope, so diagonally to the left, you would go up 2 and across 1. Also, since the sign is "<" you would graph with a dotted line. Then to know which side to shade, I always use the coordinate (0,0). I plug in 0 for both x and y to see if (0,0) satisfies the inequality. In this case it does, so you would shade on the side where (0,0) is located.
