Question

a rock is thrown straight up with an initial velocity of 21.0 m/s. ignore energy lost to air friction. how high will the rock rise?

Answer 1

Answer:

-22.5

Explanation:

We have that for the Question "A rock is thrown straight up with an initial velocity of 21.0 m/s. Ignore energy lost to air friction. How high will the rock rise?" it can be said that How high will the rock rise is

S=-21.0m

From the question we are told

A rock is thrown straight up with an initial velocity of 21.1 m/s. Ignore energy lost to air friction. How high will the rock rise?

Generally the equation for the Motion  is mathematically given as

$v2-u2=2gS$

Therefore,

$S= -(\frac{u^2}{2g} )$

$S=-(\frac{21^2}{2x9.8})$

S= -22.5