$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ \hrulefill\\[0.5em] a_3=8\\ n=3\\ d=5 \end{cases} \\\\\\ a_3=a_1+(3-1)5\implies 8=a_1+(2)5 \\\\\\ 8=a_1+10\implies -2=a_1 \\\\\\ \begin{cases} a_1=-2\\ d=5 \end{cases}\implies a_n=-2+(n-1)d$

5 0

3 years ago

What is the solution to this system

NISA [10]

Answer:

the solution to the system is (1,3)

Step-by-step explanation:

x = 1 , y = 3

5 0

3 years ago

Do I use LCM or HCF? And how can I decide which to use? (Brainliest if you can answer the whole thing)

kow [346]

Answer:

As far as i know you should go for LCM that would be more convenient and easy to do

4 0

2 years ago

SOLVE FOR M <br><br> −4m+7=−5

Masteriza [31]

Answer:

m=3

Step-by-step explanation:

-4m+7= -5

Combine like terms.Put +7 on other side.

-4m= -5-7

-4m= -12

It's -4 times m = -12 right ?

So the answer is m=3 because m= -12/-4

6 0

2 years ago

If you help ill mark as brilliant.​

If you help ill mark as brilliant.