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Oliga [24]
3 years ago
15

What is the solution to the system of equations? Use the substitution method to solve. 6=−4x+y−5x−y=21 Enter your answer in the

boxes.
Mathematics
1 answer:
miss Akunina [59]3 years ago
5 0

Answer:

x=-3 and y= -6

Step-by-step explanation:

we have

6=-4x+y and -5x-y = 21

6+4x=y we substitute y in the second equation

-5x-(6+4x)=21

-9x-6=21

-9x=27

x=-3

we substiture x in the second

-5(-3)-y =21

15-y=21

15-21=y

y=-6

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USPshnik [31]

Answer:

24

Step-by-step explanation:

8 0
3 years ago
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A graph relates the amount of gas in the tank of your car to the distance you can drive.
umka2103 [35]
The car runs out of gas, resulting in no more displacement taking place.
6 0
3 years ago
Bryan and Jadyn had barbeque potato chips and soda at a football party. Bryan ate 5 oz of chips and drank 1 cup of soda for a
MaRussiya [10]

Answer:

1 oz of chips has 120mg of sodium, while in 1 cup of soda there are 50mg of sodium.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of mg of sodium in 1 oz of chips.

y is the number of mg of sodium in a cup of soda.

Bryan ate 5 oz of chips and drank 1 cup of soda for a total of 650 mg of sodium.

This means that:

5x + y = 650

Jadyn ate 1 oz of chips and drank 5 cups of soda for a total of 250 mg of sodium.

This means that:

x + 5y = 250

From the first equation:

y = 650 - 5x

Replacing in the second

x + 5(650 - 5x) = 250

x + 3250 - 25x = 250

25x = 3000

x = \frac{3000}{25}

x = 120

y = 650 - 5x = 650 - 5*120 = 650 - 600 = 50

1 oz of chips has 120mg of sodium, while in 1 cup of soda there are 50mg of sodium.

5 0
3 years ago
If x=at^3 and y=bt^2 then find dy/dx
Molodets [167]
Dy/dx = (dy/dt) / (dx/dt)

dy/dt = 2bt

dx/dt = 3at^2

therefore dy/dx = 2bt/3at^2
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8 0
3 years ago
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schepotkina [342]

Answer:

1) y=(-1/4)x+(11/4)

2) y=(4)x-33

3) y=(2/3)x-11/3

4) y=(5)x-2

5) y=(3)x-7

6) y=(-1/4)x+(6)

Step-by-step explanation:

1) y=mx+b  3=(-1/4)(-1)+b  b= 11/4

2) y=mx+b  -5=(4)(7)+b  b= -33

3) y=mx+b  -5=(2/3)(-2)+b  b= -11/3

4) y=mx+b  3=(5)(1)+b  b= -2

5) y=mx+b  -1=(-3)(-2)+b  b= -7

6) y=mx+b  7=(1/4)(4)+b  b= 6

6 0
3 years ago
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