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2 years ago

Pls help meeeeeeeeeeee

Mathematics

2 answers:

blondinia [14]2 years ago

4 0

Answer:

8>x

Step-by-step explanation:

mr_godi [17]2 years ago

4 0

Answer:

8 > x

Step-by-step explanation:

The open circle at 8 means that x cannot be equal to 8

The arrow points left meaning that x is less than 8 , so

x < 8 , that is

8 > x

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Explain the difference between the slant height of a pyramid and the height of the pyramid.

dexar [7]

See the diagram below.
$h$ is the height, and $s$ is the slant height.

The height is the distance from the base of the pyramid to the vertex (the top of the pyramid). It runs perpendicular to the base.

The slant height is the distance from the base of the triangles which make up its sides to the vertex. It runs perpendicular to this base as well.

5 0

3 years ago

) f) 1 + cot²a = cosec²a

notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

$\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}$

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

$\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}$

Another identity is:

$\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}$

Therefore:

$\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}$

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

$\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}$

Another identity:

$\displaystyle \large{\sin^2x+\cos^2x=1}$

Therefore:

$\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}$

Hence proved, this is proof by using identity helping to find the specific identity.

6 0

3 years ago

Find the value of X. pls help me

bogdanovich [222]

Answer:

x=7

Step-by-step explanation:

As seen from the higher two numbers, there is a distinct ratio between the shorter side and the longer side. To find the ratio we simply get the given two without the x and we get 8:12 which simplifies to 2:3 or 1: 1.5

This means in order to find 3x-6, we need to multiply 10 by 1.5 which means:

3x-6=15

3x=21

x=7

Hope this helped!

5 0

4 years ago

If you have 3/12 of an orange how many fourths do you have

Kobotan [32]

1/4 of the orange.
Both 3/12 and 1/4 in decimal form are 0.25

6 0

3 years ago